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VLD [36.1K]
3 years ago
8

If the mass of a planet is 0.231 mE and its radius is 0.528 rE, estimate the gravitational field g at the surface of the planet.

The gravitational acceleration on Earth is 9.8 m/s 2 and the value of the universal gravitational constant is 6.67259 × 10−11 N · m2 /kg2 . Answer in units of m/s 2 .
Physics
1 answer:
crimeas [40]3 years ago
3 0

Answer:

8.1 m/s^2

Explanation:

The strength of the gravitational field at the surface of a planet is given by

g=\frac{GM}{R^2} (1)

where

G is the gravitational constant

M is the mass of the planet

R is the radius of the planet

For the Earth:

g_E = \frac{GM_E}{R_E^2}=9.8 m/s^2

For the unknown planet,

M_X = 0.231 M_E\\R_X = 0.528 R_E

Substituting into the eq.(1), we find the gravitational acceleration of planet X relative to that of the Earth:

g_X = \frac{GM_X}{R_X^2}=\frac{G(0.231M_E)}{(0.528R_E)^2}=\frac{0.231}{0.528^2}(\frac{GM_E}{R_E^2})=0.829 g_E

And substituting g = 9.8 m/s^2,

g_X = 0.829(9.8)=8.1 m/s^2

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blondinia [14]

Answer:

Option D. ²³⁹₉₃Np

Explanation:

Let the unknown be ʸₓA.

Thus, the equation becomes:

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Next, we shall determine the x, y and A. This can be obtained as follow:

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Collect like terms

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ʸₓA => ²³⁹₉₃A => ²³⁹₉₃Np

Thus, the complete equation is:

²³⁹₉₂U —> ⁰₋₁e + ²³⁹₉₃Np

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3 years ago
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son4ous [18]
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bagirrra123 [75]

Answer:

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Explanation:

Let's convert minutes to hours so our answer can be given in a common units of km/hour:

12 minutes = 12/60  hours = 0.2 hours

Now we estimate the average velocity calculating the distance travelled over the time it took:

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3 0
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Any ss2 here (11th Grade)
Sever21 [200]

Answer:

<h2>a) 50°</h2><h2>b) 40°</h2>

Explanation:

Check the complete diagram n the attachment below

a) The angle of incidence on a plane surface is the angle between the incidence ray and the normal ray acting on a plane surface. The normal ray is the ray perpendicular to the surface while the incidence ray is the ray striking a plane surface.

According to the diagram, the angle of reflection r₂ on M₂ is 90°-g where g is the angle of glance.

Given angle of glance on M₂ to be 40°, r₂ = 90-40 = 50°

According the second law of reflection, the angle of incidence = angle of reflection, therefore i₂ = r₂ = 50° (on M₂)

Also ∠OO₂O₁ =  ∠OO₁O₂ = 40° (angle of glance on M₁){alternate angle}

The angle of incidence on M₁ = 90° - 40° = 50°

b) The angle of incidence to the surface of M₁(∠PO₁A)will be the angle of glance on M₁ which is equivalent to 40°

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Ivenika [448]

Answer:

C

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7 0
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