Answer:
Executive Orders state mandatory requirements for the Executive Branch, and have the effect of law. They are issued in relation to a law passed by Congress or based on powers granted to the President in the Constitution and must be consistent with those authorities.
Explanation:
Answer:
![74^{\circ} C](https://tex.z-dn.net/?f=74%5E%7B%5Ccirc%7D%20C)
Explanation:
We are given that
Mass of glass,![m=300 g](https://tex.z-dn.net/?f=m%3D300%20g)
![T_1=23^{\circ}](https://tex.z-dn.net/?f=T_1%3D23%5E%7B%5Ccirc%7D)
Volume,![V=236cm^3](https://tex.z-dn.net/?f=V%3D236cm%5E3)
Mass of water=![density\times volume=1\times 236=236 g](https://tex.z-dn.net/?f=density%5Ctimes%20volume%3D1%5Ctimes%20236%3D236%20g)
Density of water=![1g/cm^3](https://tex.z-dn.net/?f=1g%2Fcm%5E3)
Temperature of hot water,![T=87^{\circ}](https://tex.z-dn.net/?f=T%3D87%5E%7B%5Ccirc%7D)
Specific heat of glass,![C_g=0.2cal/g^{\circ}C](https://tex.z-dn.net/?f=C_g%3D0.2cal%2Fg%5E%7B%5Ccirc%7DC)
Specific heat of water,![C_w=1 cal/g^{\circ}C](https://tex.z-dn.net/?f=C_w%3D1%20cal%2Fg%5E%7B%5Ccirc%7DC)
![Q_{glass}=m_gC_g(T_f-T_1)=300\times 0.2(T_f-23)](https://tex.z-dn.net/?f=Q_%7Bglass%7D%3Dm_gC_g%28T_f-T_1%29%3D300%5Ctimes%200.2%28T_f-23%29)
![Q_{water}=m_wC_w(T_f-T)=236\times 1(T_f-87)](https://tex.z-dn.net/?f=Q_%7Bwater%7D%3Dm_wC_w%28T_f-T%29%3D236%5Ctimes%201%28T_f-87%29)
![Q_{glass}+Q_{water}=0](https://tex.z-dn.net/?f=Q_%7Bglass%7D%2BQ_%7Bwater%7D%3D0)
![300\times 0.2(T_f-23)+236\times 1(T_f-87)](https://tex.z-dn.net/?f=300%5Ctimes%200.2%28T_f-23%29%2B236%5Ctimes%201%28T_f-87%29)
![60T_f-1380+236T_f-20532=0](https://tex.z-dn.net/?f=60T_f-1380%2B236T_f-20532%3D0)
![296T_f=20532+1380=21912](https://tex.z-dn.net/?f=296T_f%3D20532%2B1380%3D21912)
![T_f=\frac{21912}{296}=74^{\circ} C](https://tex.z-dn.net/?f=T_f%3D%5Cfrac%7B21912%7D%7B296%7D%3D74%5E%7B%5Ccirc%7D%20C)
I'm going to assume that this gripping drama takes place on planet Earth, where the acceleration of gravity is 9.8 m/s². The solutions would be completely different if the same scenario were to play out in other places.
A ball is thrown upward with a speed of 40 m/s. Gravity decreases its upward speed (increases its downward speed) by 9.8 m/s every second.
So, the ball reaches its highest point after (40 m/s)/(9.8 m/s²) = <em>4.08 seconds</em>. At that point, it runs out of upward gas, and begins falling.
Just like so many other aspects of life, the downward fall is an exact "mirror image" of the upward trip. After another 4.08 seconds, the ball has returned to the height of the hand which flung it. In total, the ball is in the air for <em>8.16 seconds</em> up and down.
Answer:
d = 44.64 m
Explanation:
Given that,
Net force acting on the car, F = -8750 N
The mass of the car, m = 1250 kg
Initial speed of the car, u = 25 m/s
Final speed, v = 0 (it stops)
The formula for the net force is :
F = ma
a is acceleration of the car
![a=\dfrac{F}{m}\\\\a=\dfrac{-8750}{1250}\\\\a=-7\ m/s^2](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BF%7D%7Bm%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B-8750%7D%7B1250%7D%5C%5C%5C%5Ca%3D-7%5C%20m%2Fs%5E2)
Let d be the breaking distance. It can be calculated using third equation of motion as :
![v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(25)^2}{2\times (-7)}\\\\d=44.64\ m](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2ad%5C%5C%5C%5Cd%3D%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2a%7D%5C%5C%5C%5Cd%3D%5Cdfrac%7B0%5E2-%2825%29%5E2%7D%7B2%5Ctimes%20%28-7%29%7D%5C%5C%5C%5Cd%3D44.64%5C%20m)
So, the required distance covered by the car is 44.64 m.
Answer:
The friction coefficient's minimum value will be "0.173".
Explanation:
The given query seems to be incomplete. Below is the attached file of the complete question.
According to the question,
(a)
The net friction force's magnitude will be:
⇒ ![F_{net}=ma](https://tex.z-dn.net/?f=F_%7Bnet%7D%3Dma)
![=5\times 1.7](https://tex.z-dn.net/?f=%3D5%5Ctimes%201.7)
![=8.5 \ N](https://tex.z-dn.net/?f=%3D8.5%20%5C%20N)
(b)
For m₃,
⇒ ![ma=\mu m_3 g](https://tex.z-dn.net/?f=ma%3D%5Cmu%20m_3%20g)
Or,
⇒ ![\mu=\frac{a}{g}](https://tex.z-dn.net/?f=%5Cmu%3D%5Cfrac%7Ba%7D%7Bg%7D)
![=\frac{1.7}{9.8}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1.7%7D%7B9.8%7D)
![=0.173](https://tex.z-dn.net/?f=%3D0.173)