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-BARSIC- [3]
2 years ago
5

The compound Ba(NO3)2 includes _____ oxygen atoms. 6 3 5 2

Chemistry
2 answers:
love history [14]2 years ago
6 0
It includes 6 oxygen atoms
UNO [17]2 years ago
6 0

To determine the number of oxygen atoms in the given compound, barium nitrate Ba(NO3)2, we can see that in each mole of barium nitrate, there are 6 moles of oxygen atoms in it. In this problem, the correct answer is D.

6 moles of oxygen.

Explanation:

Ba(NO3)2 ,is a composite called 'barium nitrate.' It's also described as 'barium dinitrate.' Ba(NO3)2 is created up of atoms of barium (Ba), nitrogen (N) and oxygen (O). Barium nitrate is the inorganic compound with the chemical equation Ba(NO3)2. It, like most barium salts, is transparent, toxic, and water-soluble. It fires with a green flame and is an oxidizer, it is practiced in pyrotechnics.

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1) What mass of Na2CO3 is required to make 50cc of its seminormal solution?
love history [14]

Answer:

m=1.325gNa_2CO_3

Explanation:

Hello,

In this case, by considering the given seminormal solution, we infer it is a 0.5-N solution which means that we can obtain the equivalent grams as shown below for the 55 cc (0.055 L) volume:

eq-g=0.5eq-g/L*0.050L=0.025eq-g

Next, since sodium carbonate has two sodium ions with a +1 oxidation state each, we can obtain the moles:

mol=0.025eq-gNa_2CO_3*\frac{1molNa_2CO_3}{2eq-gNa_2CO_3}\\ \\mol=0.0125molNa_2CO_3

Finally, the mass is computed by using its molar mass (106 g/mol)

m=0.0125molNa_2CO_3*\frac{106gNa_2CO_3}{1molNa_2CO_3} \\\\m=1.325gNa_2CO_3

Regards.

7 0
3 years ago
Over the years, the thermite reaction has been used for welding railroad rails, in incendiary bombs, and to ignite solid-fuel ro
melamori03 [73]

<u>Answer:</u> The mass of nickel (II) oxide and aluminium that must be used is 18.8 g and 4.54 g respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For nickel:</u>

Given mass of nickel = 14.8 g

Molar mass of nickel = 58.7 g/mol

Putting values in equation 1, we get:

\text{Moles of nickel}=\frac{14.8g}{58.7g/mol}=0.252mol

For the given chemical reaction:

3NiO(s)+2Al(s)\rightarrow 3Ni(l)+Al_2O_3(s)

  • <u>For nickel (II) oxide:</u>

By Stoichiometry of the reaction:

3 moles of nickel are produced from 3 moles of nickel (II) oxide

So, 0.252 moles of nickel will be produced from \frac{3}{3}\times 0.252=0.252mol of nickel (II) oxide

Now, calculating the mass of nickel (II) oxide by using equation 1:

Molar mass of nickel (II) oxide = 74.7 g/mol

Moles of nickel (II) oxide = 0.252 moles

Putting values in equation 1, we get:

0.252mol=\frac{\text{Mass of nickel (II) oxide}}{74.7g/mol}\\\\\text{Mass of nickel (II) oxide}=(0.252mol\times 74.7g/mol)=18.8g

  • <u>For aluminium:</u>

By Stoichiometry of the reaction:

3 moles of nickel are produced from 2 moles of aluminium

So, 0.252 moles of nickel will be produced from \frac{2}{3}\times 0.252=0.168mol of aluminium

Now, calculating the mass of aluminium by using equation 1:

Molar mass of aluminium = 27 g/mol

Moles of aluminium = 0.168 moles

Putting values in equation 1, we get:

0.168mol=\frac{\text{Mass of aluminium}}{27g/mol}\\\\\text{Mass of aluminium}=(0.168mol\times 27g/mol)=4.54g

Hence, the mass of nickel (II) oxide and aluminium that must be used is 18.8 g and 4.54 g respectively.

4 0
3 years ago
What is the mass, in grams, of a liquid having a density of 1.50g/mL and a volume of 3500mL
mojhsa [17]

Answer:

5,250g

Explanation:

Density = Mass / Volume

*Note: mass = x

1.50g/mL = x / 3500mL

multiply 3500mL on both sides

1.50g/mL * 3500mL = 3500mL(x) / 3500mL

cancel units

x = 5250g

5 0
2 years ago
An evacuated 276 mL glass bulb weighs 129.6375 g. Filled with an unknown gas, the bulb weighs 130.0318 g. Calculate the gas dens
baherus [9]

Answer:

density=1.43 g/L

Explanation:

Since the density formula is density = mass / volume, we need to find out the mass of the gas and the volume is that of the container.

The mass of the gas is  130.0318 g-129.6375 g=0.3943 g

The gas volume is  276mL*(1L/1000mL) 0.276 L

density = mass / volume=0.3943g/0.276L

density =1.43g/L

5 0
3 years ago
Which statement describes how chemical formulas, such as H2O, represent compounds
grandymaker [24]

Answer:

Which statements describe how chemical formulas, such as H2O, represent compounds? ... They show the elements that make up a compound. They show the types of atoms that make up a molecule. They show the number of each type of atom in a molecule.

5 0
3 years ago
Read 2 more answers
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