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telo118 [61]
3 years ago
9

Hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Chemistry
1 answer:
MAVERICK [17]3 years ago
6 0

Answer:

huh?

Explanation:

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Explain why the 4s sublevel fills before the 3d begins to fill as electrons are added.
tamaranim1 [39]

Answer: The energy of the 4-s subshell is lower than the energy of 3-d subshell.

Explanation:

During the filling of electrons in subshells, the lower energy levels are filled before the higher energy levels. Also known as Aufbau principle.

Energy of the sublevel = (n + l)

where : n = Principal quantum number

             l = Azimuthal quantum number(s=0,p=1,d=2,f=3)

Energy of 4-s subshell= (4+0) = 4

Energy of 3-d subshell=(3+2) = 5

Energy of 4-s subshell is lower than the energy of 3-d subshell, that is why 4s orbital is filled before the 3-d subshell.

4 0
3 years ago
Read 2 more answers
How many liters of solution will contain 1.5 moles of CaCl2 if the solution is 6.0 M CaCl2?
sashaice [31]

Answer:

0.25

Explanation:

volume= number of moles over concentration

hence v=1.5/6

6 0
3 years ago
Which of the following describes a compound?
Gemiola [76]

A compound is two or more chemically combined elements. Fore example NaCl, CO2, H2O

8 0
3 years ago
can someone explain how this is wrong? I don’t think it is wrong but my chem teacher deducted points. so why?
ruslelena [56]

Answer: measure the mass (48.425g) of KCl

Explanation:

To prepare the solution 0.65M KCl we must measure the mass of KCl that would be dissolved in 1L of the solution. This can be achieved by:

Molar Mass of KCl = 39 + 35.5 = 74.5g/mol

Number of mole (n) = 0.65

Mass conc of KCl = n x molar Mass

Mass conc of KCl = 0.65 x 74.5 = 48.425g

Therefore, to make 0.65M KCl, we must measure 48.425g

7 0
3 years ago
What volume is occupied by 8.7 g of chlorine gas, Cl2, at 23°C and 1.15 atm pressure
Harrizon [31]

Answer:

V = 5.17L

Explanation:

Mass of gas = 8.7g

T = 23°C = (23 + 273.15)K = 296.15K

P = 1.15 atm

V = ?

R = 0.082atm.L / mol.K

From ideal gas equation

PV = nRT

P = pressure of the gas

V = volume of the gas

n = no. Of moles

R = ideal gas constant

T = temperature of the gas

no of moles = mass / molar mass

Molar mass of Chlorine = 35.5g / mol

No. Of moles = 8.7 / 35.5

No. Of moles = 0.245 moles

PV = nRT

V = nRT / P

V = (0.245 * 0.082 * 296.15) / 1.15

V = 5.9496 / 1.15

V = 5.17L

The volume of the gas is 5.17L

4 0
3 years ago
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