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telo118 [61]
2 years ago
9

Hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Chemistry
1 answer:
MAVERICK [17]2 years ago
6 0

Answer:

huh?

Explanation:

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A sample of an unknown gas at STP has a density of 0.630 gram per liter. What is the gram molecular mass of this gas?
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<span>STP means standard temperature and pressure at 0°C (273K) and 1 atm (atmosphere). The density of the unknown gas is 0.63 gram per liter. The deal gas equation is PV = nRT. The n is the numer of moles and can be represented as mass of the gas, m, divided by the molar mass, c.  so we have,</span>  

PV = nRT
PV = (m/c)RT
Since the density is d = m/V
Pc = (m/V)RT
Pc = dRT
c = drT/P  

substitute the values into the equation,
c = [(0.63g/L)(0.08206 L-atm/mol-K)(273K)]/(1atm)
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3 years ago
Use the References to access important values if needed for this question There are 12 eggs in a dozen. If a farmer's chickens p
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Answer:

3.4\times 10^3 eggs are produces are in a month.

Explanation:

Quantity of eggs produced by the chicken in a month = 284 dozens

1 dozen = 12 eggs

Number of eggs in a month:

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3.4\times 10^3 eggs are produces are in a month.

4 0
2 years ago
Calculate the rate constant at 200.°C for a reaction that has a rate constant of 8.30 × 10−4 s−1 at 90.°C and an activation ener
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Answer:

23.0 s⁻¹ is rate constant

Explanation:

Using the Arrhenius equation:

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Where k is rate constant

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R is gas constant (8.314J/molK)

And T is absolute temperature (24°C + 273 = 297K)

Replacing:

k = 1.5x10¹¹s⁻¹ * e^(-55800J/mol/8.314J/molK*297K)

k = 1.5x10¹¹s⁻¹ * 1.53x10⁻¹⁰

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Explanation:

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2 significant figures
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