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telo118 [61]
3 years ago
9

Hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Chemistry
1 answer:
MAVERICK [17]3 years ago
6 0

Answer:

huh?

Explanation:

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For pH= 4.00 :

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Microwave ovens emit microwave energy with a wavelength of .129 m. What is the energy of exactly one photon of this microwave ra
gayaneshka [121]

λ=Wavelength = .129 m = 0.129 m

E = energy = ?

h =Planck constant = 6.63 × 10^-34 J.s

f = frequency of photo/ electromagnetic radiation = c/λ

c = Speed of light in a vacuum = 3 × 10^8 m/s

___o___o___

E = hf \\  \\ E = h \frac{c}{λ}  \\  \\ E = 6.63 \times  {10}^{ - 34}  \frac{3 \times  {10}^{8} }{0.129}  \\  \\ E =  \frac{6.63 \times  {10}^{ - 34}  \times 3 \times  {10}^{8} }{0.129}  \\  \\ E =  \frac{663 \times  {10}^{ - 36}  \times 3 \times  {10}^{8} }{129 \times  {10}^{ - 3} }  \\  \\E =  \frac{1989 \times  {10}^{ - 28} }{129 \times  {10}^{ - 3} }   \\  \\ E = 15.4 \times  {10}^{ - 25} J \\  \\ E = 1.54 \times  {10}^{ - 24} J

I hope I helped you^_^

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3 years ago
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