Answer:
131 minutes, an = 15 + (n - 1)(4)
Step-by-step explanation:
each time she is increasing by 4 minutes
we can write this equation like this since we have the difference and the first part:
an = 15 + (n - 1)(4)
note
"an" (or ace of n)'s n is in subscript and is written just like a superscript but on the bottom
we can plug in this equation to find ace of 30 (a30)
15 + (30 - 1)(4)
15 + 29*4
116 + 15
a30 = 131
Answer:
7.6 seconds
Step-by-step explanation:
To solve this problem we can use the following equation:
S = So + 113*t + at^2/2
Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.
In this problem, we have that S = 0, So = 65, Vo = 113 and a = -32 ft/s2 (The acceleration of gravity)
So we have that:
0 = 65 + 113t - 16t2
16t2 - 113t - 65 = 0
Using Bhaskara's formula, we have:
Delta = 113^2 + 4*65*16 = 16929
sqrt(Delta) = 130.11
t = (113 + 130.11) / (2*16) = 7.597 seconds
Rounding to nearest tenth, we have t = 7.6 seconds
Answer:the answer is 18
Step-by-step explanation:You do 9minus three then get six and then multiply six by three to get 18.
