Question

A bullet of mass 0.01 kg is fired in to a sand bas of mass 0.49 kg from a tree. The Sand bag with the bullet embedded in to it swings a way at lo m/s find a The momentum after the Collision b, The momentum befor the Collision the velocity of the bullet ​

Answer 1

Since the bag was at rest, its initial momentum is zero. The velocity of the ball before collision is 500 ms-1.

Linear momentum

The term momentum in physics refers the product of mass and velocity. If we know mass of the object and its velocity, then we calculate the momentum.

Momentum before collision for the bullet = 0.01 kg × v

Momentum before collision for the bag = 0

Momentum after collision for the bag and bullet = (0.01 kg  +  0.49 kg) 10 = 5 Kgms-1

The velocity of the bullet before collision =  0.01 kg × v + 0 =  5 Kgms-1

v = 5 Kgms-1/0.01 kg

v = 500 ms-1

Learn more about momentum: brainly.com/question/904448

Answer 2

Answer:

$(0.01kg \times 0.49)10ms = 5kgms$