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Hope this helps....
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Theorem: If two chords intersect within a circle, then the product of the lengths of the segments (parts) of one chord is equal to the product of the lengths of the segments of the other chord.
In oyur case,

Solve this equation to find x:

Answer: 6, choice B.
Dhsksggsosnsbsbsndjhdisjdbdgisjdbdbd
The graphed polynomial seems to have a degree of 2, so the degree can be 4 and not 5.
<h3>
Could the graphed function have a degree 4?</h3>
For a polynomial of degree N, we have (N - 1) changes of curvature.
This means that a quadratic function (degree 2) has only one change (like in the graph).
Then for a cubic function (degree 3) there are two, and so on.
So. a polynomial of degree 4 should have 3 changes. Naturally, if the coefficients of the powers 4 and 3 are really small, the function will behave like a quadratic for smaller values of x, but for larger values of x the terms of higher power will affect more, while here we only see that as x grows, the arms of the graph only go upwards (we don't know what happens after).
Then we can write:
y = a*x^4 + c*x^2 + d
That is a polynomial of degree 4, but if we choose x^2 = u
y = a*u^2 + c*u + d
So it is equivalent to a quadratic polynomial.
Then the graph can represent a function of degree 4 (but not 5, as we can't perform the same trick with an odd power).
If you want to learn more about polynomials:
brainly.com/question/4142886
#SPJ1
Answer:
G= 56/3
Step-by-step explanation:
56/3 is an ugly number if you ask me but it was the answer I got, and here's how I got it!
So first off you want to change -49 to a positive and add it to 7! This will change the equation to 3g=56, from here just divide 56 by 3! Which if you don't turn into a fraction it'll just be a really long number. So g=56/3! If you have any more questions feel free to ask!