Reaction equation:
Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
Moles of Al(OH)₃:
moles = mass/Mr
= 1.51 / (27 + 17 x 3)
= 0.019
Molar ratio Al(OH)₃ : HCl = 1 : 3
Moles of HCl required = 0.019 x 3
=0.057
concentration = moles/volume
volume = 0.057 / 0.1
= 0.57 dm³
= 570 ml
The cell notation is:

here in cell notation the left side represent the anodic half cell where right side represents the cathodic half cell
in anodic half cell : oxidation takes place [loss of electrons]
in cathodic half cell: reduction takes place [gain of electrons]
1) this is a galvanic cell
2) the standard potential of cell will be obtained by subtracting the standard reduction potential of anode from cathode


Therefore

3) as the value of emf is positive the reaction will be spontaneous as the free energy change of reaction will be negative
Δ
As reaction is spontaneous and there will be conversion of chemical energy to electrical energy it is a galvanic cell.
Answer:
The answer to your question is: P = 419933.5 Pa
Explanation:
Data
R = 0.287 KJ/Kg°K = 287 J/Kg°K
mass = 2 kg
T = 35 °C = 308°K
Container = 0.750 meters each side
Volume = l x l x l
= 0.750 x 0.750 x 0.750
= 0.421 m³
P = mRT / V
P = (2)(287)(308) / 0.421
P = 176792 / 0.421
P = 419933.5 Pa
Explanation:
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