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Anna35 [415]
3 years ago
7

Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas: pcl3(g+cl2(g?pcl5(g. a 7.5-l gas vessel

is charged with a mixture of pcl3(g and cl2(g, which is allowed to equilibrate at 450 k. at equilibrium the partial pressures of the three gases are ppcl3 = 0.129 atm , pcl2 = 0.155 atm , and ppcl5 = 1.30 atm. does the equilibrium favor reactants or products?
Chemistry
1 answer:
Natasha2012 [34]3 years ago
6 0
25655+6565++65+65+65+56+566+56+556+5+656+56+56+56+56+
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Fill in the Blank
Arisa [49]

Answer: Quantitative data

Explanation:

3 0
3 years ago
Calculate the standard enthalpy change for the reaction at 25 ∘ 25 ∘ C. Standard enthalpy of formation values can be found in th
WINSTONCH [101]

<u>Answer:</u> The standard enthalpy change of the reaction is coming out to be -16.3 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

Mg(OH)_2(s)+2HCl(g)\rightarrow MgCl_2(s)+2H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]

We are given:

\Delta H_f_{(Mg(OH)_2(s))}=-924.5kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H_f_{(MgCl_2(s))}=-641.8kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-641.8))+(2\times (-241.8))]-[(1\times (-924.5))+(2\times (-92.30))]\\\\\Delta H_{rxn}=-16.3kJ

Hence, the standard enthalpy change of the reaction is coming out to be -16.3 kJ

6 0
3 years ago
A dehydration reaction (or condensation reaction) is the process in which _____.
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A. The bonds between the individual monomers of a polymer are broken by the addition of water molecules.
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4 years ago
How many nanometers are in 0.0006245101 km?
maw [93]

Answer:

624510100

Explanation:

Doing a conversion factor:

0,0006245101[km]*\frac{1000[m]}{1 km} *\frac{1x10^{9} nanometer}{1 m} =624510100 [nanometer]

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In a chemical interaction 10 g of hydrogen chloride is added to 20 g of zinc to form 24 g of zinc chloride and a certain amount
dybincka [34]
6g of hydrogen gas is my answer. I'm sorry if I'm wrong.
7 0
3 years ago
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