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Anna35 [415]
4 years ago
7

Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas: pcl3(g+cl2(g?pcl5(g. a 7.5-l gas vessel

is charged with a mixture of pcl3(g and cl2(g, which is allowed to equilibrate at 450 k. at equilibrium the partial pressures of the three gases are ppcl3 = 0.129 atm , pcl2 = 0.155 atm , and ppcl5 = 1.30 atm. does the equilibrium favor reactants or products?
Chemistry
1 answer:
Natasha2012 [34]4 years ago
6 0
25655+6565++65+65+65+56+566+56+556+5+656+56+56+56+56+
You might be interested in
If a jet's cruising altitude is 32,200 ft (to three significant figures), this distance in km is: (1 mile = 1.61 km; 1 mile = 52
DochEvi [55]

If a jet's cruising altitude is 32,200 ft (to three significant figures), this distance in km is 9.82 km.

<h3>What are significant figures?</h3>

Significant figures are the number of digits in a value, often a measurement, that contributes to the degree of accuracy of the value. We start counting significant figures at the first non-zero digit.

In this case, given the conversion factors from miles to kilometres and from miles to feet, we can directly compute the jet’s cruising altitude in kilometres as shown below:

32200 ft X \frac{1 mile}{5280 ft}  X \frac{1.61km}{1 mile}

=9.82 km

Learn more about the significant figures here:

brainly.com/question/14359464

#SPJ1

6 0
2 years ago
Three samples of a solid substance composed of elements A and Z were prepared. The first contained 4.31 g A and 7.70 g Z. The se
murzikaleks [220]

Answer:

The percentage composition of the elements of the compound in the three samples is the same.

Explanation:

<em>The law of definite proportions states that all pure samples of a particular chemical compound contain the same elements in the same proportion by mass.</em>

Sample A:

Mass of A = 4.31 g; mass of Z = 7.70 g

Total mass of sample = 12.01

Percentage mass of A in the sample = (4.31 * 100)/12.01 = 35.9 %

Percentage mass of Z in the sample = (7.70 * 100)/12.01 = 64.1 %

Sample B:

Percentage mass of A in the sample = 35.9 %

Percentage mass of Z in the sample = 64.1 %

Sample C:

Mass of A = 0.718 g; Total mass of sample = 2.00 g

mass of Z = mass of sample - mass of A = 2.00 g - 0.718 g = 1.282 g

Percentage mass of A in the sample = (0.718 * 100)/2.00 = 35.9 %

Percentage mass of Z in the sample = (1.282 * 100)/2.00 = 64.1 %

From the calculations, it can be seen that the percentage composition of the elements in the compound is the same for the three samples.

8 0
4 years ago
a solution is made by dissolving 14.57 g of sodium bromide nabr in 415 of water . what is the molality of the solution?
jenyasd209 [6]

Answer:

The answer to your question is molality = 0.34

Explanation:

Data

mass of NaBr = 14.57 g

mass of water = 415 g.

molality = ?

Process

1.- Calculate the molar mass of NaBr

NaBr = 23 + 80 = 103 g

2.- Calculate the moles of NaBr

                     103 g of NaBr ------------------ 1 mol

                      14.57 g of NaBr ---------------  x

                               x = (14.57 x 1) / 103

                               x = 14.57 / 103

                               x = 0.141 moles

3.- Calculate the molality

molality = moles / volume

-Substitution

molality = 0.141 / .415

-Result

molality = 0.34

4 0
3 years ago
Read 2 more answers
The diagram below shows changes to the nucleus of an atom.
anzhelika [568]

Answer:

maybe 1 or 3 im not sure

Explanation:

i didn't study it yet sorry for not helping but try asking someone else

8 0
3 years ago
Read 2 more answers
Kc is 1.67 × 1020 at 25°C for the formation of iron(III) oxalate complex ion: Fe3+(aq) + 3 C2O42-(aq) ⇌ [Fe(C2O4)3]3-(aq). If 0.
AleksandrR [38]

Answer:

hello? are you still here? reply if you are

8 0
3 years ago
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