3 years ago

Why would an atomic nucleus give off a particle?

Physics

1 answer:

expeople1 [14]3 years ago

6 0

They give off a particle to become stable.

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What is pH? (NEED ANSWER ASAP)

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Answer:

the answer is A

Explanation:

pH is a measure of how acidic/basic water

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3 years ago

Write the type of simple machine shown in the diagram gn the line by its number.

Elanso [62]

2. Wheel and axle
3.fulcrum
6.wheel and axle (I think) hope this helps!

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2 years ago

A rock with a mass of 2.0 kg falls from a cliff. At a height of 5.0 meters, its velocity is 6.0 m/s. What is the mechanical ener

REY [17]

Answer : The mechanical energy of the rock is, 134 J

Solution :

As we know that the mechanical energy is equal to the sum of the kinetic energy and the potential energy.

The formula used for mechanical energy is,

$M.E=K.E+P.E\\\\M.E=(\frac{1}{2}mv^2)+(mgh)$

where,

M.E = mechanical energy

K.E = kinetic energy

P.E = potential energy

m = mass of an object = 2 Kg

v = velocity of an object = 6 m/s

h = height = 5 m

g = acceleration due to gravity = $9.8m/s^2$

Now put all the given values in the above formula, we get the mechanical energy of the rock.

$M.E=[\frac{1}{2}(2Kg)\times (6m/s)^2]+(2Kg\times 9.8m/s^2\times 5m)=134\text{ Kg }m^2s^{-2}=134J$

Therefore, the mechanical energy of the rock is, 134 J

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3 years ago

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Suppose heat has caused convection currents to from in a fluid. When the heat source is removed from the fluid, the convection c

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3 years ago

1. Swordfish are capable of stunning output power for short bursts. A 650 kg swordfish has a cross-sectional area of 0.92 m2 and

Oksana_A [137]

Answer:

$P_{sp}=178.4W/kg$

Explanation:

From the question we are told that:

Mass of fish $m_f=650kg$

Cross-sectional area $A=0.92 m^2$

Drag coefficient of $\mu= 0.0091$

Seawater density $\rho= 1026 kg/m^3.$

Speed of Fish $v=30 m/s$

Generally the equation for Drag force F_d is mathematically given by

$F_d = \mu * \rho *A v^2 /2$

$F_d = 0.0091* 0.92* 1026* 30^2/2 \\F_d= 3865. 35 N$

Generally the equation for high speed Power $P_{sp}$ is mathematically given by

$P_{sp}=3865*35*\frac{v}{m_f}$

$P_{sp}=F_d*35*\frac{30}{650}$

$P_{sp}=178.4W/kg$

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3 years ago