Answer:
Both objects travel the same distance.
(c) is correct option
Explanation:
Given that,
Mass of first object = 4.0 kg
Speed of first object = 2.0 m/s
Mass of second object = 1.0 kg
Speed of second object = 4.0 m/s
We need to calculate the stopping distance
For first particle
Using equation of motion
Where, v = final velocity
u = initial velocity
s = distance
Put the value in the equation
....(I)
Using newton law
Now, put the value of a in equation (I)
Now, For second object
Using equation of motion
Put the value in the equation
....(I)
Using newton law
Now, put the value of a in equation (I)
Hence, Both objects travel the same distance.
We know, For a substance they both are equal in magnitude, i.e.,
Specific Gravity = Density
Specific Gravity = 19.3 [ As Density = 19.3 ]
In short, option C would be your correct Answer!
Hope this helps!
Mirror formula
1/f = (1/p) + (1/q) [ f= focal length , p= object distance , q = image distance ]
as given convex mirror so
distance of object =p= 6cm
focal length = -8cm
to find q=?
1/q =( 1/f) - (1/ p)
1/q = (1/ 8) -(1/6)
1/q =-1/24
q=-24 ( negative sign shows image is virtual and behind the mirror)
Answer:
The correct option is;
(c) 64W
Explanation:
Here we have the Coefficient Of Performance, COP given by
The heat change from 23° to 6°C for a mass of 10 kg/h which is equivalent to 10/(60×60) kg/s or 2.78 g/s we have
= m·c·ΔT = 2.78 × 4.18 × (23 - 6) = 197.39 J
Therefore, plugging in the value for in the COP equation we get;
which gives
Since we were working with mass flow rate then the power input is the same as the work done per second and the power input to the refrigerator = 63.674 J/s ≈ 64 W.
The power input to the refrigerator is approximately 64 W.
Answer:
100m
Explanation:
100m
s=ut+1/2at^2
s= unknown, u=0, a=2, t=10
s=0*10+1/2(2)(10)^2
s=1/2(2)(100)
s=1(100)
displacement = 100 meters
