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3 years ago

The current through a heater is 12 A when it is plugged into a

Physics

1 answer:

jasenka [17]3 years ago

7 0

Answer:

A. 10Ω

Explanation:

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es la atmósfera que se percibe en un cuento de acuerdo a la manera de pensar y sentir de los personajes no se ve sólo se siente

masya89 [10]

Answer:

can you please ask in english

8 0

2 years ago

Please I really need help on these

blagie [28]

Answer:

3, 4, 2

Explanation:

I can't see the final ones.

4 0

3 years ago

On a cold day, a heat pump absorbs heat from the outside air at 14°F (−10°C) and transfers it into a home at a temperature of 86

Leto [7]

Answer:

6.575

Explanation:

T1 = 30C = 30 + 273 = 303 K

T2 = - 10 C = - 10 + 273 = 263 K

The coefficient of performance of heat pump

k = T2 / (T1 - T2)

k = 263 / (303 - 263) = 6.575

7 0

3 years ago

The mass of a carbon atom is 12. 00amu while the mass of a helium-4 atom is 4. 003amu. If three atoms of helium fuse to form car

Naily [24]

If three atoms of helium fuse to form carbon than 0.009 u of mass is converted into energy

Given: m(He) = 4.003 u

and m(C) = 12.000 u

Mass of 3 alpha particles =3×4.003 u

=12.009 u.

Mass of 1 carbon atom=12.000 u

Mass Defect =△m=12.009−12.000=0.009 u

Energy released =0.009×931.5=8.3835 MeV.

So, 0.009 u of mass is converted into 8.38 Mev energy.

To learn more about Fusion visit here; brainly.com/question/14445690?referrer=searchResults

#SPJ4

4 0

1 year ago

A violinist is tuning her instrument to concert A (440 Hz). She plays the note while listening to an electronically generated to

Soloha48 [4]

To solve the problem it is necessary to take into account the concepts related to beat frequency, i.e., The number of those wobbles per second.

The equation that describes the beat frequency is

$f_{beat} = |f_2-f_1|$

For our given case we have that the frequency of the instrument is 440Hz and the Beat frequency is 5Hz therefore,

A) The frequency of the violin would be given by

$f_{beat} = |f_2-f_1|$

$5Hz = |f_2-440Hz|$

$f_2 = 440 \pm 5$

$f_2 = 445Hz or 435Hz$

B) <em>The violinist must loosen the string.</em> As the tightening increases the frequency, thereby increasing the number of beats from 5 to 6, i. e, on thightening the string, the frequency further increases as high frequency will be produced by short trings.

5 0

3 years ago