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Rainbow [258]
3 years ago
8

The current through a heater is 12 A when it is plugged into a

Physics
1 answer:
jasenka [17]3 years ago
7 0

Answer:

A. 10Ω

Explanation:

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masya89 [10]

Answer:

can you please ask in english

8 0
2 years ago
Please I really need help on these
blagie [28]

Answer:

  3, 4, 2

Explanation:

I can't see the final ones.

4 0
3 years ago
On a cold day, a heat pump absorbs heat from the outside air at 14°F (−10°C) and transfers it into a home at a temperature of 86
Leto [7]

Answer:

6.575

Explanation:

T1 = 30C = 30 + 273 = 303 K

T2 = - 10 C = - 10 + 273 = 263 K

The coefficient of performance of heat pump

k = T2 / (T1 - T2)

k = 263 / (303 - 263) = 6.575

7 0
3 years ago
The mass of a carbon atom is 12. 00amu while the mass of a helium-4 atom is 4. 003amu. If three atoms of helium fuse to form car
Naily [24]

If three atoms of helium fuse to form carbon than 0.009 u of mass is converted into energy

Given: m(He) = 4.003 u

and m(C) = 12.000 u

Mass of 3 alpha particles =3×4.003 u

                                       =12.009 u.

Mass of 1 carbon atom=12.000 u

Mass Defect =△m=12.009−12.000=0.009 u

Energy released =0.009×931.5=8.3835 MeV.

So, 0.009 u of mass is converted into 8.38 Mev energy.

To learn more about Fusion visit here; brainly.com/question/14445690?referrer=searchResults

#SPJ4

4 0
1 year ago
A violinist is tuning her instrument to concert A (440 Hz). She plays the note while listening to an electronically generated to
Soloha48 [4]

To solve the problem it is necessary to take into account the concepts related to beat frequency, i.e., The number of those wobbles per second.

The equation that describes the beat frequency is

f_{beat} = |f_2-f_1|

For our given case we have that the frequency of the instrument is 440Hz and the Beat frequency is 5Hz therefore,

A) The frequency of the violin would be given by

f_{beat} = |f_2-f_1|

5Hz = |f_2-440Hz|

f_2 = 440 \pm 5

f_2 = 445Hz or 435Hz

B) <em>The violinist must loosen the string.</em> As the tightening increases the frequency, thereby increasing the number of beats from 5 to 6, i. e, on thightening the string, the frequency further increases as high frequency will be produced by short trings.

5 0
3 years ago
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