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Diano4ka-milaya [45]
3 years ago
5

The density of a material is calculated by:

Physics
1 answer:
anyanavicka [17]3 years ago
5 0

Answer:

The density of the material is defined as the mass of the material to its volume.

                           ρ = M / V

Explanation:

The density of the material is a scalar quantity.

If the mass and the volume of the material is known the density of the material can be calculated using the formula,

                                     ρ = M / V

The mass of the material can be found using a physical balance.

The volume of a geometrically symmetrical material can be found using the geometrical measurement. For a brick,

                                              V = l x b x h

For non-geometrically shaped material the volume can be found from the displacement method using water.

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SELECT ALL THAT APPLY!! Which of the following are considered SIGNS that a chemical reaction occurred?
MAXImum [283]

Answer:

Formation of a Precipitate

Unexpected Color Change

Formation of a Gas

Explanation:

8 0
3 years ago
Technetium (Tc; Z = 43) is a synthetic element used as a radioactive tracer in medical studies. A Tc atom emits a beta particle
LenKa [72]

Answer : The de-Broglie wavelength of this electron, 0.101\AA

Explanation :

The formula used for kinetic energy is,

K.E=\frac{1}{2}mv^2        ..........(1)

According to de-Broglie, the expression for wavelength is,

\lambda=\frac{h}{mv}

or,

v=\frac{h}{m\lambda}      ...........(2)

Now put the equation (2) in equation (1), we get:

\lambda=\frac{h}{\sqrt{2\times m\times K.E}}  ...........(3)

where,

\lambda = wavelength = ?

h = Planck's constant = 6.626\times 10^{-34}Js

m = mass of electron = 9.11\times 10^{-31}Kg

K.E = kinetic energy = 4.71\times 10^{-15}J

Now put all the given values in the above formula (3), we get:

\lambda=\frac{6.626\times 10^{-34}Js}{\sqrt{2\times 9.11\times 10^{-31}Kg\times 4.71\times 10^{-15}J}}

\lambda=1.0115\times 10^{-11}m=0.101\AA

conversion used : (1\AA=10^{-10}m)

Therefore, the de-Broglie wavelength of this electron, 0.101\AA

7 0
3 years ago
a 10kg ball is thrown into the air. it is going 3m/s when thrown. How much potential energy will it have at the top?
Alexandra [31]

Answer:

45 J

Explanation:

Assuming the level at which the ball is thrown upwards is the ground level,

We can use the equations of motion to obtain the maximum height covered by the ball and then calculate the potential energy

u = initial velocity of the ball = 3 m/s

h = y = vertical distance covered by the ball = ?

v = final velocity of the ball at the maximum height = 0 m/s

g = acceleration due to gravity = -9.8 m/s²

v² = u² + 2ay

0 = 3² + 2(-9.8)(y)

19.6y = 9

y = (9/19.6)

y = 0.459 m

The potential energy the ball will have at the top of its motion = mgh

mgh = (10)(9.8)(0.459) = 45 J

Hope this Helps!!!

7 0
3 years ago
Where might you look on the internet to find good scientific information about illness
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It depends on what illness and what country you are in but Mayo Clinic and Johns Hopkins are good sources.
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3 years ago
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