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igor_vitrenko [27]
3 years ago
5

How much force can a 2.5 kg sledge hammer excerpt on a nail if you can swing the hammer at 20 m/s and the hammer contacts the na

il for 0.08 seconds?
Physics
1 answer:
AleksAgata [21]3 years ago
4 0

Answer:

625 N

Explanation:

The impulse given to the nail is equal to the change in momentum of the hammer:

I=F \Delta t=m \Delta v

where

F is the force exerted by the hammer

\Delta t=0.08 s is the time of contact

m=2.5 kg is the mass

\Delta v=20 m/s is the change in velocity of the hammer

Substituting the data and re-arranging the equation, we can find the force:

F=\frac{m \Delta v}{\Delta t}=\frac{(2.5 kg)(20 m/s)}{0.08 s}=625 N

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