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igor_vitrenko [27]
3 years ago
5

How much force can a 2.5 kg sledge hammer excerpt on a nail if you can swing the hammer at 20 m/s and the hammer contacts the na

il for 0.08 seconds?
Physics
1 answer:
AleksAgata [21]3 years ago
4 0

Answer:

625 N

Explanation:

The impulse given to the nail is equal to the change in momentum of the hammer:

I=F \Delta t=m \Delta v

where

F is the force exerted by the hammer

\Delta t=0.08 s is the time of contact

m=2.5 kg is the mass

\Delta v=20 m/s is the change in velocity of the hammer

Substituting the data and re-arranging the equation, we can find the force:

F=\frac{m \Delta v}{\Delta t}=\frac{(2.5 kg)(20 m/s)}{0.08 s}=625 N

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What is the name of the unit you use to measure force?
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Answer:

that would be newtons.

Explanation:

I hope this helps

8 0
2 years ago
An airplane flies in a horizontal circle of radius 500 m at a speed of 150 m/s. If the radius were changed to 1000 m, but the sp
laila [671]

Answer:

The centripetal acceleration changed by a factor of 0.5

Explanation:

Given;

first radius of the horizontal circle, r₁ = 500 m

speed of the airplane, v = 150 m/s

second radius of the airplane, r₂ = 1000 m

Centripetal acceleration is given as;

a = \frac{v^2}{r}

At constant speed, we will have;

v^2 =ar\\\\v = \sqrt{ar}\\\\at \ constant\ v;\\\sqrt{a_1r_1} = \sqrt{a_2r_2}\\\\a_1r_1 = a_2r_2\\\\a_2 = \frac{a_1r_1}{r_2} \\\\a_2 = \frac{a_1*500}{1000}\\\\a_2 = \frac{a_1}{2} \\\\a_2 = \frac{1}{2} a_1

a₂ = 0.5a₁

Therefore, the centripetal acceleration changed by a factor of 0.5

7 0
3 years ago
A 1600kg cannon fires a 5kg cannonball horizontally. The exit velocity of the cannonball is 80m/s and the barrel length is 2m. W
evablogger [386]

Answer:

 a = 1600 m / s²

Explanation:

For this exercise we use the kinematics relations,

         v² = v₀² + 2 a x

where v₀ is the initial velocity of the bullet, which as part of rest is zero, for the distance (x) we can assume that the gases accelerate along the entire trajectory of the cannon x = 2m

         a = \frac{v^2}{2x}

let's calculate

         a = \frac{80^2}{2 \ 2}

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7 0
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A bond between a positively-charged particle and a negatively-charged particle is a(n) _______ bond.
weeeeeb [17]
The answer is an ionic bond.
6 0
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The density of a hippo is approximately 1030kg/m^3,so it sinks to the bottom of the freshwater lakes and rivers. A 1500kg hippo
hram777 [196]

Answer:

14,700 N

Explanation:

The hyppo is standing completely submerged on the bottom of the lake. Since it is still, it means that the net force acting on it is zero: so, the weight of the hyppo (W), pushing downward, is balanced by the upward normal force, N:

W-N=0 (1)

the weight of the hyppo is

W=mg=(1500 kg)(9.8 m/s^2)=14,700 N

where m is the hyppo's mass and g is the gravitational acceleration; therefore, solving eq.(1) for N, we find

N=W=14,700 N

8 0
3 years ago
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