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Softa [21]
3 years ago
13

A team of ecologists are studying four different ecosystems with varying levels of biodiversity. The ecologists categorize the d

ifferent levels of biodiversity for the four ecosystems as shown in the table below.
Genetic Diversity Species Diversity Habitat Diversity
Ecosystem A Low Low Medium
Ecosystem B Medium High Medium
Ecosystem C High Low Low
Ecosystem D Medium Low High
Based on the information above, which ecosystem most likely experienced a recent population bottleneck?


Ecosystem A, because its low genetic diversity could have resulted from an event that reduced the variation in the gene pool.

Ecosystem A, because its low genetic diversity could have resulted from an event that reduced the variation in the gene pool.
A

Ecosystem B, because its high species diversity could have resulted from increased competition among its members.

Ecosystem B, because its high species diversity could have resulted from increased competition among its members.
B

Ecosystem C, because its low habitat diversity indicates an increase in available niches.

Ecosystem C, because its low habitat diversity indicates an increase in available niches.
C

Ecosystem D, because its low species diversity indicates that it also has low species evenness.
Physics
1 answer:
Ann [662]3 years ago
4 0

Answer:

B. Ecosystem B, because its high species diversity could have resulted from increased competition among its members.

Explanation:

This is because, in the  ecosystem with varying level of biodiversity, Ecosystem B has medium level of species diversity found in them with High medium level of habitat diversity which causes increasing competitions among them.

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A girl rolls a ball up an incline and allows it to re- turn to her. For the angle and ball involved, the acceleration of the bal
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Answer:

3.28 m

3.28 s

Explanation:

We can adopt a system of reference with an axis along the incline, the origin being at the position of the girl and the positive X axis going up slope.

Then we know that the ball is subject to a constant acceleration of 0.25*g (2.45 m/s^2) pointing down slope. Since the acceleration is constant we can use the equation for constant acceleration:

X(t) = X0 + V0 * t + 1/2 * a * t^2

X0 = 0

V0 = 4 m/s

a = -2.45 m/s^2 (because the acceleration is down slope)

Then:

X(t) = 4*t - 1.22*t^2

And the equation for speed is:

V(t) = V0 + a * t

V(t) = 4 - 2.45 * t

If we equate this to zero we can find the moment where it stops and begins rolling down, that will be the highest point:

0 = 4 - 2.45 * t

4 = 2.45 * t

t = 1.63 s

Replacing that time on the position equation:

X(1.63) = 4 * 1.63 - 1.22 * 1.63^2 = 3.28 m

To find the time it will take to return we equate the position equation to zero:

0 = 4 * t - 1.22 * t^2

Since this is a quadratic equation it will have to answers, one will be the moment the ball was released (t = 0), the other will eb the moment when it returns:

0 = t * (4 - 1.22*t)

t1 = 0

0 = 4 - 1.22*t2

1.22 * t2 = 4

t2 = 3.28 s

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Answer:

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Explanation:

Using a driver while at least 350 yds away is better than using a iron, because it will be a waste of the par 4 as it is not as powerful as the driver.

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