Answer:
The greatest acceleration the man can give the airplane is 0.0059 m/s².
Explanation:
Given that,
Mass of man = 85 kg
Mass of airplane = 109000 kg
Distance = 9.08
Coefficient of static friction = 0.77
We need to calculate the greatest friction force
Using formula of friction

Where, m = mass of man
g = acceleration due to gravity
Put the value into the formula


We need to calculate the acceleration
Using formula of newton's second law


Put the value into the formula


Hence, The greatest acceleration the man can give the airplane is 0.0059 m/s².
Answer:
Explanation:
it is a vector as it has a magnitude and a direction. If it was a scalar quantity it would just have a magnitude and would be 45 m. Acceleration is an example of a vector quantity
Answer:
The terminal velocity is 
Explanation:
From the question we are told that
The mass of the squirrel is 
The surface area is 
The height of fall is h =4.8 m
The length of the prism is 
The width of the prism is 
The terminal velocity is mathematically represented as

Where
is the density of a rectangular prism with a constant values of 
is the drag coefficient for a horizontal skydiver with a value = 1
A is the area of the prism the squirrel is assumed to be which is mathematically represented as


substituting values


Answer:
is b and d hope id helpful
Explanation:
idk how to explain