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Softa [21]
3 years ago
13

A team of ecologists are studying four different ecosystems with varying levels of biodiversity. The ecologists categorize the d

ifferent levels of biodiversity for the four ecosystems as shown in the table below.
Genetic Diversity Species Diversity Habitat Diversity
Ecosystem A Low Low Medium
Ecosystem B Medium High Medium
Ecosystem C High Low Low
Ecosystem D Medium Low High
Based on the information above, which ecosystem most likely experienced a recent population bottleneck?


Ecosystem A, because its low genetic diversity could have resulted from an event that reduced the variation in the gene pool.

Ecosystem A, because its low genetic diversity could have resulted from an event that reduced the variation in the gene pool.
A

Ecosystem B, because its high species diversity could have resulted from increased competition among its members.

Ecosystem B, because its high species diversity could have resulted from increased competition among its members.
B

Ecosystem C, because its low habitat diversity indicates an increase in available niches.

Ecosystem C, because its low habitat diversity indicates an increase in available niches.
C

Ecosystem D, because its low species diversity indicates that it also has low species evenness.
Physics
1 answer:
Ann [662]3 years ago
4 0

Answer:

B. Ecosystem B, because its high species diversity could have resulted from increased competition among its members.

Explanation:

This is because, in the  ecosystem with varying level of biodiversity, Ecosystem B has medium level of species diversity found in them with High medium level of habitat diversity which causes increasing competitions among them.

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Which occurs when a wave is reflected?
dmitriy555 [2]

Answer: The wave can flip upside down.

Reflection is the bending of a wave when it cannot pass through. For example, plain mirrors which are flat, a ray of light hits the mirror and is reflected from the mirror since it cannot pass through  

When reflection occurs the speed and frequency of the wave does not change but the wave is flipped upside down.

The speed does not change because speed is affected by the change in medium the frequency also remains the same since the energy of the wave does not change.


3 0
3 years ago
Read 2 more answers
6. An aircraft is is travelling along a runway at a Velocity of 25m/s in It accelerates at a rate of 4m/s² for a distance of 750
zysi [14]

Answer:

Take-off velocity = v = 81.39[m/s]

Explanation:

We can calculate the takeoff speed easily, using the following kinematic equation.

v_{f}^{2}=v_{i}^{2} +2*a*x

where:

a = acceleration = 4[m/s^2]

x = distance = 750[m]

vi = initial velocity = 25 [m/s]

vf = final velocity

v_{f}=\sqrt{(25)^{2}+(2*4*750) } \\v_{f}=81.39[m/s]

7 0
3 years ago
El espectro visible en el aire está comprendido entre la longitud de onda 450 nm del color azul, Determina la velocidad de propa
TiliK225 [7]

Answer:

v = 2,99913 10⁸ m / s

Explanation:

The velocity of propagation of a wave is

         v = λ f

in the case of an electromagnetic wave in a vacuum the speed that speed of light

         v = c

When the wave reaches a material medium, it is transmitted through a resonant type process, whereby the molecules of the medium vibrate at the same frequency as the wave, as the speed of the wave decreases the only way that they remain the relationship is that the donut length changes in the material medium

         λ = λ₀ / n

where n is the index of refraction of the material medium.

Therefore the expression is

           v = \frac{\lambda_o}{n} f

Let's look for the frequency of blue light in a vacuum

           f =\frac{c }{\lambda_o}  

           f = \frac{3 \ 10^8}{450 \ 10^{-9}}

           f = 6.667 10¹⁴ Hz

the refractive index of air is tabulated

           n = 1,00029

let's calculate

           v = \frac{450 \ 10^{-9} }{1.00029}  \ 6.667 \ 10^{14}450 10-9 / 1,00029 6,667 1014

            v = 2,99913 10⁸ m / s

we can see that the decrease in speed is very small

8 0
3 years ago
An object is dropped from a height of 25 meters. At what velocity will it hit the ground?
Goryan [66]
You can use Vf^2-Vi^2 = 2ax

Vf^2 - 0 = 2(9.81)(25)

Or you can use energy

mgh = 1/2mv^2

2gh =v^2

Same thing
6 0
3 years ago
A low C (f=65Hz) is sounded on a piano. If the length of the piano wire is 2.0 m and
WITCHER [35]

Answer:

T = 676 N

Explanation:

Given that: f = 65 Hz, L = 2.0 m, and ρ = 5.0 g/m^{2} = 0.005 kg

A stationary wave that is set up in the string has a frequency of;

f = \frac{1}{2L}\sqrt{\frac{T}{M} }

⇒      T = 4L^{2}f^{2}M

Where: t is the tension in the wire, L is the length of the wire, f is the frequency of the waves produced by the wire and M is the mass per unit length of the wire.

But M = L × ρ = (2 × 0.005) = 0.01 kg/m

T = 4 × 2^{2} ×65^{2} × 0.01

   = 4 × 4 ×4225 × 0.01

   = 676 N

Tension of the wire is 676 N.

4 0
3 years ago
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