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Softa [21]
3 years ago
13

A team of ecologists are studying four different ecosystems with varying levels of biodiversity. The ecologists categorize the d

ifferent levels of biodiversity for the four ecosystems as shown in the table below.
Genetic Diversity Species Diversity Habitat Diversity
Ecosystem A Low Low Medium
Ecosystem B Medium High Medium
Ecosystem C High Low Low
Ecosystem D Medium Low High
Based on the information above, which ecosystem most likely experienced a recent population bottleneck?


Ecosystem A, because its low genetic diversity could have resulted from an event that reduced the variation in the gene pool.

Ecosystem A, because its low genetic diversity could have resulted from an event that reduced the variation in the gene pool.
A

Ecosystem B, because its high species diversity could have resulted from increased competition among its members.

Ecosystem B, because its high species diversity could have resulted from increased competition among its members.
B

Ecosystem C, because its low habitat diversity indicates an increase in available niches.

Ecosystem C, because its low habitat diversity indicates an increase in available niches.
C

Ecosystem D, because its low species diversity indicates that it also has low species evenness.
Physics
1 answer:
Ann [662]3 years ago
4 0

Answer:

B. Ecosystem B, because its high species diversity could have resulted from increased competition among its members.

Explanation:

This is because, in the  ecosystem with varying level of biodiversity, Ecosystem B has medium level of species diversity found in them with High medium level of habitat diversity which causes increasing competitions among them.

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Answer:

B_0 = 1.69 \times 10^{-4}\ T

Explanation:

given,

total deflection = 4.12 cm

Electric field = 1.1 ×10³ V/m

plate length = 6 cm

distance between them = 12 cm

using formula

v_0 = \sqrt{\dfrac{q\epsilon_0d}{ym}(\dfrac{d}{2}+L)}

q = 1.6 × 10⁻¹⁹ C

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v_0 = \sqrt{\dfrac{1.6 \times 10^{-19}\times 1.1 \times 10^{3}\times 0.06}{0.0412\times 9.11 \times 10^{-31} }(\dfrac{0.06}{2}+0.12)}

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v_0 = \dfrac{E}{B_0}

B_0 = \dfrac{E}{v_0}

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