Answer:
he fall movement we see that both the force is different from zero, and the torque is different from zero.
When analyzing the statements the d is true
Explanation:
Let's pose the solution of this problem, to be able to analyze the firm affirmations.
When the person is falling, the weight acts on them all the time, initially the rope has no force, but at the moment it begins to lash it exerts a force towards the top that is proportional to the lengthening of the rope.
The equation for this part is
Fe - W = m a
k x - mg = m a
As the axis of rotation is located at the top where they jump, there is a torque.
What is it
Fe y - W y = I α
angular and linear acceleration are related
a = α r
Fe y - W y = I a / r
In the fall movement we see that both the force is different from zero, and the torque is different from zero.
When analyzing the statements the d is true
Answer:
r = 0.5 m
Explanation:
First we find the angular speed of the ball by using its period:
ω = θ/t
For the time period:
ω = angular speed = ?
θ = angular displacement = 2π rad
t = time period = 0.5 s
Therefore,
ω = 2π rad/0.5 s
ω = 12.56 rad/s
Now, for the radius:
v = rω
r = v/ω
where,
v = linear speed = 6.29 m/s
r = radius = ?
r = (6.29 m/s)/(12.56 rad/s)
<u>r = 0.5 m</u>
Answer:
ΔL = 3.82 10⁻⁴ m
Explanation:
This is a thermal expansion exercise
ΔL = α L₀ ΔT
ΔT = T_f - T₀
where ΔL is the change in length and ΔT is the change in temperature
Let's reduce the length to SI units
L₀ = 90.5 mm (1m / 1000 mm) = 0.0905 m
let's calculate
ΔL = 25.10⁻⁶ 0.0905 (154.6 - (14.4))
ΔL = 3.8236 10⁻⁴ m
using the criterion of three significant figures
ΔL = 3.82 10⁻⁴ m
Concaved lenses...........
Still go straight but would obviously go up in speed!!
Hope this helps plz mark as brainlist and 5 star
