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Akimi4 [234]
3 years ago
14

A resistor with an unknown resistance is connected in parallel to a 13 ? resistor. when both resistors are connected in parallel

to an emf source of 13 v, the current through the unknown resistor is measured with an ammeter to be 3
a. what is the resistance of the unknown resistor? answer in units of ?.

Physics
1 answer:
DENIUS [597]3 years ago
4 0
Hope this helps you.

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If approximately equal volumes of an acid and a bace of a equal strength are combined the resulting solutin should have a pH of
Phoenix [80]

The answer is around 7.

As the acid and the base are of equal strength, they neutralize each other and the resulting solution is neutral (pH≈7).

Hope this helps you!

3 0
4 years ago
Read 2 more answers
Electromagnetism consists of what two processes?
kherson [118]

Answer: it’s A and B

Explanation: everyone else on this post was giving you the wrong answer.

5 0
3 years ago
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A coin is dropped in a 15.0 m deep well.
labwork [276]

Answer:

t = 1.75

t = 0.04

Explanation:

a)

For part 1 we want to use a kenamatic equation with constant acceleration:

X = 1/2*a*t^2

isolate time

t = sqrt(2X / a)

Plugin known variables. Acceleration is the force of gravity which is 9.8 m/s^2

t = sqrt(2*15m / 9.8m/s^2)

t = 1.75 s

b)

The speed of sound travels at a constant speed therefore we don't need acceleration and can use the equation:

v = d / t

isolate time

t = d / v

plug in known variables

t = 15m / 340m/s

t = 0.04 s

7 0
3 years ago
Assignment 10 Coulombic Equation Practice Directions: Complete the following problems to calculate the electrostatic force that
Tatiana [17]

Answer:

Magnitude of the force between the charges is F = 1.92×10^20N

Explanation:

Given the magnitude of force according to coulombs law

F =K[(q1*q2)/r2]

Where q1 and q2 are the charges

r is the distance between the charges

K is the coulombs constant

Substituting the given values, we have;

F = 8.98×10^9 × 1.5×10^6 × 3.2×10^4/1.5²

F = 43.1×10^19/2.25

F = 19.16×10^19N

F = 1.92×10^20N

8 0
3 years ago
Dx= 7.14m and Dy = -7.55m<br> What is the direction and magnitude of the vector
KengaRu [80]

The Magnitude of the Vector is 10.39m and the direction of the vector is - 46.7°.

<u>Explanation:</u>

GIven dx=7.14m and dy= -7.55m,

The Magnitude of the Vector=\sqrt{dy^{2} +dx^{2} }

Magnitude d= \sqrt{(7.14)^{2} +(-7.55)^{2} } .

                  d=\sqrt{50.97+57}

                  d=\sqrt{107.98}

                  d= 10.39m.

Direction Ф = tan^{-1}\frac{dy}{dx}

                      =tan^{-1} \frac{-7.55}{7.14}      

                      = tan^{-1}(-1.06)

                Ф    = - 46.7°.

5 0
3 years ago
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