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3 years ago

Which quantity is a vector quantity A. Acceleration B. Mass C. Speed D. Volume

Physics

1 answer:

Marianna [84]3 years ago

5 0

Answer:

Acceleration

Explanation:

A vector quantity has a magnitude and direction. Mass, Speed and Volume are all scalar quantities because they only have magnitude, and not direction.

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You push on a 30 kg box with a force of 120 N. What is the acceleration of the box2

kumpel [21]

Answer:

Explanation:

120/30=6

8 0

3 years ago

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denis23 [38]

Answer:

Friction: When two surfaces slide against each other / make contact with each other

Force: A push or pull exerted on an object

8 0

3 years ago

Bill is farsighted and has a near point located 121 cm from his eyes. Anne is also farsighted, but her near point is 74.0 cm fro

Arada [10]

Answer:

Explanation:

The lens equation is

1 / f = 1 / di + 1 / do

Where

f is focal length

di is the image distance

do is the object distance

Both Annie and Billy use a glass whose near point is 25cm

Then, the object distance is

do = 25 - 2 = 23cm

The have the same object distance.

Let find the vocal length of bills eye

Given that,

Bill near point is 121cm and distance of the glass from the eye is 2cm

Then,

Image distance of bill is

di_B = -(121-2) = -119cm

object distance do = 23cm

Then,

1 / f_B = 1 / di_B + 1 / do

1 / f_B = -1 / 119 + 1 / 23

1 / f_B = -119^-1 + 23^-1

1 / f_B = 0.0351

Then, f_B = 28.51 cm

Also, let find Annie focal length

Given that,

Annie near point is 74 cm and distance of the glass from the eye is 2cm

Then,

Image distance of Annie is

di_A = -(74-2) = -72cm

object distance do = 23cm

Then,

1 / f_A = 1 / di_A + 1 / do

1 / f_A = -1 / 72 + 1 / 23

1 / f_A = -72^-1 + 23^-1

1 / f_A = 0.02959

Then, f_A = 33.8 cm

Distance of object from the lens when Annie uses Billy glass

Then,

1 / f_B = 1 / di_A + 1 / do

1 / 28.51 = -1 / 72 + 1 / do

28.51^-1 = -72^-1 + do^-1

do^-1 = 28.51^-1 + 72^-1

do^-1 = 0.048964

do = 20.42 cm

Then, the object location from the eye will be, the eye is 2cm from the glass. Then,

do_A = 20.42 + 2 = 22.42cm

do_A = 22.42 cm

Distance of object from the lens when Billy uses Annie glass

Then,

1 / f_A = 1 / di_B + 1 / do

1 / 33.8 = -1 / 119 + 1 / do

33.8^-1 = -119^-1 + do^-1

do^-1 = 33.8^-1 + 119^-1

do^-1 = 0.03799

do = 26.32 cm

Then, the object location from the eye will be, the eye is 2cm from the glass. Then,

do_B = 26.32 + 2 = 28.32 cm

do_B = 28.32 cm

7 0

3 years ago

Huck Finn walks at a speed of 0.70 m/s across his raft (that is, he walks perpendicular to the raft’s motion relative to the sho

ZanzabumX [31]

Answer

given,

Hunk Finn speed,v_y= 0.7 m/s

Speed of river,v_x = 1.50 m/s

Assuming the speed of the river is in x-direction.

Speed of Hunk Finn to be in y-direction.

Hunk velocity relative to river =

$x = \sqrt{v_y^2+v_x^2}$

$x = \sqrt{2.74}$

$x =1.66\ m/s$

Speed of Hunk relative to river = 1.66 m/s

direction of the boat

$\theta =tan^{-1}(\dfrac{v_y}{v_x})$

$\theta =tan^{-1}(\dfrac{0.7}{1.50})$

$\theta = 25.01^{\circ}$

Hence, angle of the raft is 24.01°

6 0

4 years ago

A weight of 50.0 N is suspended from a spring that has a force constant of 210 N/m. The system is undamped and is subjected to a

Fittoniya [83]

Answer:

The maximum value of the driving force is 1044.01 N.

Explanation:

Given that,

Weight of the object, W = 50 N

Force constant of the spring, k = 210 N/m

The system is undamped and is subjected to a harmonic driving force of frequency 11.5 Hz.

Amplitude, A = 4 cm

We need to find the maximum value of the driving force. The force is given by the product of mass and maximum acceleration as :

$F=mA\omega^2$ .....(1)

A is amplitude

m is mass,

$m=\dfrac{W}{g}\\\\m=\dfrac{50}{10}\\\\m=5\ kg$

$\omega$ is angular frequency

Angular frequency is given by :

$\omega=2\pi f\\\\\omega=2\pi \times 11.5\\\\\omega=72.25\ rad/s$

Equation (1) becomes :

$F=5\times 0.04\times 72.25^2\\\\F=1044.01\ N$

So, the maximum value of the driving force is 1044.01 N.

6 0

3 years ago