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2 years ago

6

Is a hockey player moving at a constant velocity across frictionless ice, balance or unbalance

1 answer:

daser333 [38]2 years ago

6 0

Answer:

Balanced

Explanation:

An unbalanced force will cause a change in the velocity, either the speed or direction, thus if the object is moving at a constant velocity that indicates that there is no acceleration or change in velocity which means that the forces are balanced.

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If an object is accelerating at 4 m/s^2 and has a mass of 8 kg, what is the net

Salsk061 [2.6K]

Answer:

The force applied is 32 N

Explanation:

F = ma

F = 8 × 4

F = 32 N

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2 years ago

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A marble statue has a mass of 6,200 grams and a volume of 2,296 cm3. What is the density of marble?

Elan Coil [88]

D= m/v
d= 6200/2296
density = about 2.7

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3 years ago

Dianne's teacher has a chunk of dry ice for the class to look at. Dry ice is a kind of frozen gas—it is very cold. The teacher w

Gelneren [198K]

The answer is A. Hope this helps you with your work.

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2 years ago

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A 740-kg boulder is raised from a quarry 119 m deep by a long uniform chain having a mass of 550 kg . This chain is of uniform s

Naddika [18.5K]

Answer:

A) the maximum acceleration the boulder can have and still get out of the quarry

B) how long does it take to be lifted out at maximum acceleration if it started from rest

Explanation:

A)

let +y is upward. look below at the free body diagram. the mass M refers to the combined mass of the boulder and chain.

the weight of the chain is: $w_{c} =m_{c} g$ and maximum tension is $T=2.50 m_{c} g=1.41*10^4N$

total mass and weight is :

$M =m_{c}+ m_{b} =740kg+550kg=1290 kg$

$w_{M} =1.2650*10^4N$

∑ $F_{y} =ma_{y}$

$T-M_{g} =Ma_{y}$

$a_{y} =(t-M_{g} )/M=(2.50m_{c} -M_{g} )/M=(2.50.550kg-1290kg)(9.8m/s^2)/1290kg$

$=0.645m/s^2$

B)

maximum acceleration

$a_{y} =0.645m/s^2\\\\y-y_{0} =119m\\v_{0y} =0$

using $y-y_{0} =v_{oy} t+1/2(a_{y} )t^2$

to solve for t

$t=\sqrt{2(y-y_{0} )/a_{y} }$

$t=\sqrt{2(119m)/0.645m/s^2} =19.20s$

6 0

3 years ago

You are traveling at 100 km/hr to make it to work on time. You have to be to work in .25 hr or you will be late. You have 16 km

alexgriva [62]

Answer: Yes

Explanation:

Velocity $V$ is defined as the distance traveled $d$ in a specific time $t$ :

$V=\frac{d}{t}$

If you are traveling at $V=100 km/h$ a distance $d=16 m$ , then the time it will take you to be at work is:

$t=\frac{d}{V}=\frac{16 km}{100 km/h}$

$t=0.16 h$

This means you will make it on time, because this time is less than 0.25 h.

4 0

3 years ago