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3 years ago

Is a hockey player moving at a constant velocity across frictionless ice, balance or unbalance

Physics

1 answer:

daser333 [38]3 years ago

6 0

Answer:

Balanced

Explanation:

An unbalanced force will cause a change in the velocity, either the speed or direction, thus if the object is moving at a constant velocity that indicates that there is no acceleration or change in velocity which means that the forces are balanced.

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What is the current flowing through a 10 resistor in a parallel circuit with a 120 V potential difference across it?

Elena L [17]

Answer:

let current flow be x

Explanation:

than we know potential difference = energy supply / charge then 120 = 10 /x then x=12 therefore pd = 12 v

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3 years ago

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kirill [66]

Answer:

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3 years ago

The gas within a cylinder of an engine undergoes a net change in volume of 1.50 × 10-3 m3 when it does work at a constant press

Lemur [1.5K]

Answer:

work =p×v =3.27×10^5×1.5×10^-3 =490.5 joule

efficiency =w/q in

:. qin= w/efficiency =490.5/0.225=2180 joule

qout =q in - work =1689.5 joule

q out is work given as heat

4 0

4 years ago

A helicopter flying west begins experiencing an acceleration of 3m/s2 east. Will the magnitude of its velocity increase or decre

Rama09 [41]

The acceleration measures the change in velocity.

Since the acceleration is in the direction opposite to the speed, the velocity eastwards will decrease : its magnitude will first decrease, then it reach 0 m/s, then finally it will increase again.

3 0

3 years ago

The mass of the moon is 7.36×1022kg and its distance to the Earth is 3.84×108m. What is the gravitational force of the moon on t

marissa [1.9K]

Answer:

The gravitational force is F = $2\,*\,10^{20}\,N$

Explanation:

To answer this question we need to recall Newton's Universal Law of Gravitation for the force "F" exerted from one object to the other:

$F=G\,\frac{m_1\,*\,m_2}{d^2}$

where G is the Universal gravitational constant = $6.674\,* \,10^{-11}\,\,\frac{m^3}{kg\,s^2}$

$m_1$ , and $m_2$ are the masses of the two bodies/objects attracting each other via gravitational force. In our case, one is the mass of the Earth = $5.972\,*\,10^{24}\, kg$

and the other one,the mass of the Moon = $7.36\,*\,10^{22}\,kg$

and lastly, "d" is the distance between to two objects. In our case:

d = $3.84\,*\,10^8\,m$

Since all these quantities are given in SI units, when we use them in the formula, our answer will result in the SI units of force "N" (Newtons):

$F=6.674\,*10^{-11}\,\frac{5.972\,10^{24}\,7.36\,10^{22}}{(3.84\,10^8)^2} \,N\\F=1.989\,*\,10^{20}\,N\\$

which can be rounded to: F = $2\,*\,10^{20}\,N$

8 0

3 years ago