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3 years ago

What is the main cause of erosion

2 answers:

5 0

Erosion is caused by human activities like excessive construction, agriculture, surface mining and forestry. Removing the vegetative cover accelerates erosion, which is often caused by grazing, logging or cultivating. In some cases, it can be removed by pests like pigs, rabbits and goats.

inna [77]3 years ago

3 0

Erosion is mainly caused by water, wind, and gravity.

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Which of the following has the highest frequency?

rewona [7]

B. 100% sure

Have a good day/night

3 0

3 years ago

Read 2 more answers

You plan to take your hair blower to europe, where the electrical outlets put out 240 v instead of the 120 v seen in the united

Dmitrij [34]

P = U × I
I = P / U = 1600W / 120V = 13.4A
P = 240V × 13.4A = 3216W

If your hair blower isnt rated for 220- 230V(this is the voltage in EU) you are most likely going to burn it.

8 0

3 years ago

A block of mass m rests on a frictionless, horizontal surface. A cord attached to the block passes over a pulley whose radius is

ra1l [238]

Answer:

Explanation:

Let the tension in the cord be T₁ and T₂ .

for motion of block placed on horizontal table

T₁ = m a , a is acceleration of the whole system .

for motion of hanging bucket of mass m

mg - T₂ = ma

adding the two equation

mg + T₁- T₂ = 2ma

for rotational motion of the pulley

torque = moment of inertia x angular acceleration

(T₂ - T₁) R = I x α , I is moment of inertia of pulley , α is angular acceleration .

(mg - 2ma ) R = I x α

(mg - 2ma ) R = I x a / R

(mg - 2ma ) R² = I x a

mgR² = 2ma R² + I x a

a = mgR² / (2m R² + I )

Since body moves by distance d in time T

d = 1/2 a T²

a = 2d / T²

mgR² / (2m R² + I ) = 2d / T²

mgR²T² = 2d x (2m R² + I )

mgR²T² - 4dm R² = 2dI

m R² ( gT² - 4d ) = 2dI

I = m R² ( gT² - 4d ) ] / 2d .

3 0

4 years ago

The system below uses massless pulleys and ropes. The coefficient of friction is μ. Assume that M1 and M2 are sliding. Gravity i

Archy [21]

Explanation:

Using Newtons second law on each block

F = m*a

Block 1

$T_{1} - u*g*M_{1} = M_{1} *a \\\\T_{1} = M_{1}*(a + u*g) ... Eq1$

Block 2

$T_{2} - u*g*M_{2} = M_{2} *a \\\\T_{2} = M_{2}*(a + u*g) ... Eq2$

Block 3

$- (T_{1} + T_{2} ) + g*M_{3} = M_{3} *a \\\\T_{1} + T_{2} = M_{3}*( -a + g) ... Eq3$

Solving Eq1,2,3 simultaneously

Divide 1 and 2

$\frac{T_{1} }{T_{2}} = \frac{M_{1}*(a+u*g)}{M_{2}*(a+u*g)} \\\\\frac{T_{1} }{T_{2}} = \frac{M_{1} }{M_{2} }\\\\ T_{1} = \frac{M_{1} *T_{2} }{M_{2} } .... Eq4$