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zhuklara [117]
3 years ago
6

Apply Concepts Why do most tall

Chemistry
1 answer:
fgiga [73]3 years ago
6 0
Because heat does not rise
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How explain two ways to decrease the energy of a wave
Aleks04 [339]

Answer:

gravity that's what I rellat think it is

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3 years ago
Calculate the percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl on the assumption that t
stealth61 [152]

Answer:

1.089%

Explanation:

From;

ν =1/2πc(k/meff)^1/2

Where;

ν = wave number

meff = reduced mass or effective mass

k = force constant

c= speed of light

Let

ν =1/2πc (k/meff)^1/2  vibrational wave number for 23Na35 Cl

ν' =1/2πc(k'/m'eff)^1/2 vibrational wave number for 23Na37 Cl

The between the two is obtained from;

ν' - ν /ν  = (k'/m'eff)^1/2 - (k/meff)^1/2 / (k/meff)^1/2

Therefore;

ν' - ν /ν = [meff/m'eff]^1/2 - 1

Substituting values, we have;

ν' - ν /ν = [(22.9898 * 34.9688/22.9898 + 34.9688) * (22.9898 + 36.9651/22.9898 * 36.9651)]^1/2  -1

ν' - ν /ν = -0.01089

percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl;

ν' - ν /ν * 100

|(-0.01089)|  × 100 = 1.089%

4 0
3 years ago
A chemist carefully measures the amount of heat needed to raise the temperature of a 894.0g sample of a pure substance from to −
astraxan [27]

Answer:

C = 0.2349 J/ (g °C)

Explanation:

Mass, m = 894.0g

Initial Temperature = −5.8°C

Final Temperature =  17.5°C

Temperature change = 17.5°C - (−5.8°C) = 23.3

Heat, H = 4.90kJ = 4900 J

Specific heat capacit, C = ?

The relationship between these quantities is given by the equation;

H = mCΔT

C = H / mΔT

C = 4900 / (894)(23.3)

C = 0.2349 J/ (g °C)

4 0
3 years ago
I need help pleasee
Readme [11.4K]

Answer:

Explanation:

6. Where on the graph does adding heat energy NOT raise the temperature?

What is the heat energy DOING if it's not raising the temperature?  :its being compressed I believe its vaporizing

7. What is temperature A called?  Freezing

8. What is temperature B called? Vaporizing

4 0
3 years ago
A student carefully placed 15.6 g of sodium in a reactor supplied with chlorine gas. When the reaction was complete, the student
BabaBlast [244]

Answer:

24.09 grams of chlorine gas reacted.

Explanation:

2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)

Moles of sodium chloride = \frac{39.7 g}{58.5 g/mol}=0.6786 mol

According to reaction, 2 moles of  NaCl are formed from 1 mole chlorine gas.

Then 0.6786 moles of NaCl will be formed from;

\frac{1}{2}\times 0.6786 mole=0.3393 mol

Mass of 0.3393 moles of chlorine  gas:

0.3393 mol × 71 g/mol = 24.09 g

24.09 grams of chlorine gas reacted.

5 0
3 years ago
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