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katen-ka-za [31]
3 years ago
6

Why does the moon appear to move across the sky

Chemistry
1 answer:
arsen [322]3 years ago
3 0
Hello the moon is not moving but it is going through the lunar cycle. The picture is a blood moon

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A gas has a volume of 340.0 mL at 45.90 oC. What is the new temperature of the gas, in Kelvin, if the volume increased to 550.0
d1i1m1o1n [39]

Answer:

Solution for A gas has a volume of 340.0 mL at 45.90 degree celsius. What is the new temperature of the gas, in kelvin, if the volume increased to 550.0 mL.

Missing: oC. ‎| Must include: oC.

Explanation:

6 0
3 years ago
Hexane and heptane are miscible with each other in all proportions. In making a solution of them, is the entropy of the system i
Damm [24]

Answer: Option (a) is the correct answer.

Explanation:

A miscible solution is defined as the one in which two or more than two components are soluble with each other.

So, when hexane is added to heptane then both of them will mix with each other and hence they are miscible. This mixing will lead to formation of more number of ions into the solution as a result, more will be the disorder present in the solution.

As entropy is the degree of randomness present.

Hence, we can conclude that a solution of hexane and heptane will lead to an increase in entropy.

8 0
3 years ago
Is a sauce a substance or mixture?
Komok [63]

Answer:

I would say that a sauce is a mixture, only because everything that makes up a sauce is all mixed together and turned into one thing, it isn't all separate.

5 0
3 years ago
What mass of precipitate forms when 185.5 ml of 0.533 m naoh is added to 627 ml of a solution that contains 15.8 g of aluminum s
Law Incorporation [45]

Answer:

2,57 g of precipitate.

Explanation:

For the reaction:

6 NaOH + Al₂(SO₄)₃ → 2 Al(OH)₃ + 3 Na₂SO₄

The precipitate is Al(OH)₃.

185,5mL of 0,533M NaOH are:

0,1855L × 0,533M = <em>0,0989 moles NaOH</em>

Moles of Al₂(SO₄)₃ are:

15,8g × \frac{1mol}{342,15g} = <em>0,0462 moles Al₂(SO₄)₃</em>

For the total reaction of 0,0989 moles NaOH with Al₂(SO₄)₃ you need:

0,0989moles NaOH × \frac{1molAl_{2}(SO_{4})_{3}}{6 moles NaOH} = <em>0,0165 moles Al₂(SO₄)₃</em>

As you have <em>0,0462 moles Al₂(SO₄)₃ </em>the limiting reactant is NaOH.

0,0989 moles of NaOH produce:

0,0989moles NaOH × \frac{2molAl(OH)_{3}}{6 moles NaOH} = <em>0,0330 moles of Al(OH)₃</em>

These moles are:

0,0330 moles of Al(OH)₃ × (78 g/mol) = <em>2,57 g of Al(OH)₃ ≡ mass of precipitate</em>

<em></em>

I hope it helps!

<em> </em>

3 0
3 years ago
¿cual es la expresion matematica para dos magnitudes que se relacionan de una forma directamente proporcional?
DENIUS [597]

Answer:

4

Explanation:

I guess it says more about the problem

3 0
2 years ago
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