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3 years ago

5

What did both Newton and Einstein believe directly affects gravity? mass of objects distance between objects curvature of object

s acceleration of objects

1 answer:

timurjin [86]3 years ago

6 0

Answer:

mass of objects

Explanation:

hope it helps

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An ambulance is currently traveling at 15m/s, and is accelerating with a constant acceleration of 5 m/s^2. The ambulance is atte

Lorico [155]

initial velocity=15m/s=u
Acceleration=a=5m/s^2
Final velocity=v=30m/s
Distance be s

Using 3rd equation of kinematics

$\\ \rm\longmapsto v^2-u^2=2as$

$\\ \rm\longmapsto s=\dfrac{v^2-u^2}{2a}$

$\\ \rm\longmapsto s=\dfrac{30^2-15^2}{2(5)}$

$\\ \rm\longmapsto s=\dfrac{900-225}{10}$

$\\ \rm\longmapsto s=\dfrac{675}{10}$

$\\ \rm\longmapsto s=67.5m$

5 0

3 years ago

A 2000 g of C 14 is left to decay radioactively the half-life of Corbin 14 is approximately 5700 years what fraction of that sam

ahrayia [7]

Answer:

1/8

Explanation:

17,100 years is 3 times the half-life of 5,700 years. After each half-life, half remains, so the amount remaining after 3 half-lives is ...

(1/2)(1/2)(1/2) = 1/8

1/8 of the sample remains after 17,100 years.

8 0

3 years ago

Read 2 more answers

A container with volume 1.83 L is initially evacuated. Then it is filled with 0.246 g of N2. Assume that the pressure of the gas

alisha [4.7K]

Answer:

The pressure is $P = 1652 \ Pa$

Explanation:

From the question we are told that

The volume of the container is $V = 1.83 \ L = 1.83 *10^{-3 } \ m^3$

The mass of $N_2$ is $m_n = 0.246 \ g = 0.246 *10^{-3} \ kg$

The root-mean-square velocity is $v = 192 \ m/s$

The root -mean square velocity is mathematically represented as

$v = \sqrt{ \frac{3 RT}{M_n } }$

Now the ideal gas law is mathematically represented as

$PV = nRT$

=> $RT = \frac{PV}{n }$

Where n is the number of moles which is mathematically represented as

$n = \frac{ m_n }{M }$

Where M is the molar mass of $N_2$

So

$RT = \frac{PVM_n }{m _n }$

=> $v = \sqrt{ \frac{3 \frac{P* V * M_n }{m_n } }{M_n } }$

=> $v = \sqrt{ \frac{ 3 * P* V }{m_n } } }$

=> $P = \frac{v^2 * m_n}{3 * V }$

substituting values

=> $P = \frac{( 192)^2 * 0.246 *10^{-3}}{3 * 1.83 *10^{-3} }$

=> $P = 1652 \ Pa$

3 0

3 years ago

Pls help.No random links pls.

jek_recluse [69]

Answer:

I believe its the second oneee

6 0

3 years ago

Read 2 more answers

What is the de broglie wavelength of a 149-g baseball traveling at 95.4 mph? (1 mile = 1.609 km, h = 6.63 × 10–34 j·s)?

boyakko [2]

The solution for the problem is:

Wavelength = Planck’s constant/(mass*velocity)

Planck’s constant= 6.63*10^-34 with units of J-s or kg-m^2/s^2-s

mass = 149g = 0.149 kg

velocity = 95.4.mi/1hr(1609.3m/1mi)(1hr/3600sec) = 42.65m/s

h/mv = 6.63*10^-34 kg-m^2/s^2-s/(42.65m/s*0.149kg)

wavelength = 1.04 *10^-34 m

5 0

3 years ago