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Mademuasel [1]
3 years ago
9

To test the quality of water sources in her area, Shameka collects five samples from each water source and tests the quality of

each sample.
Physics
1 answer:
xenn [34]3 years ago
6 0

The missing part of the incomplete question is given below:

Which important step of scientific design is Shameka conducting?

repetition

replication

verification of results

using controlled variables

Answer:

Verification of results

Explanation:

The way toward gathering five examples of water from various sources is conveyed to confirm the outcome. By gathering water from five distinct areas of a similar source the analyst can genuinely find out the nature of the water in her region of remain.  

On the off chance that after examples are tried it is found the water isn't sound, the outcomes would be acknowledged as it has been appropriately checked and a  proper move would be made.

Thus, the correct answer is - verification of results

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A charge of +1.4×10^6 coulombs moves from point a to b. What is the potential difference between the two points if the work done
Rama09 [41]
The potential difference between the two points if the work done on the charge is +3.4×10^7 joules would be A. 10volts.
8 0
3 years ago
A 2000 g of C 14 is left to decay radioactively the half-life of Corbin 14 is approximately 5700 years what fraction of that sam
ahrayia [7]

Answer:

  1/8

Explanation:

17,100 years is 3 times the half-life of 5,700 years. After each half-life, half remains, so the amount remaining after 3 half-lives is ...

  (1/2)(1/2)(1/2) = 1/8

1/8 of the sample remains after 17,100 years.

8 0
3 years ago
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The moon's illumination changes in a periodic way that can be modeled by a trigonometric function. On the night of a full moon,
kupik [55]

Answer:

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t+7)) + 0.125

Explanation:

The expression for the  trigonometric function is :

L(t) = A (cos (B(t - C)))+ D   ----- equation (1)

where ;

A = \frac{max-min}{2}

A = \frac{0.25-0}{2}

A = 0.125

D = \frac{0+.025}{2}

D = 0.125

Period of the lunar cycle = 29.53

Then;

\frac{2 \pi}{B}  = 29.53

29.53 \ \ B = 2 \pi

B = \frac{2 \pi}{29.53}

B = \frac{\pi}{29.53}

Also; we known that December 25 is 7 days before January 1.

Then L(-7) = 0.025

Plugging all the values into trigonometric function ; we have:

0.125 ( cos ( \frac{\pi}{14.765}((-7)-C)))+0.125 = 0.25 \\ \\ \\  ( cos ( \frac{\pi}{14.765}((-7)-C))) = \frac{0.25-0.125}{0.125}

( cos ( \frac{\pi}{14.765}((-7)-C))) = 1

( \frac{\pi}{14.765}((-7)-C))= cos^{-1} (1)

}((-7)-C))=0

C= -7

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t-(-7))) + 0.125

L(t) = 0.125 (cos (\frac{\pi}{14.765}(t+7)) + 0.125

7 0
3 years ago
Which state of matter has a definite<br> volume but does not have a definite shape
creativ13 [48]

Your answer is liquids

5 0
3 years ago
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The earth travels around the sun once a year in an approximately circular orbit whose radius is 1.50x10^11 m. From this data det
seraphim [82]
(a) Determine the circumference of the Earth through the equation,
            C = 2πr
Substituting the known values, 
           C = 2π(1.50 x 10¹¹ m)
             C = 9.424 x 10¹¹ m

Then, divide the answer by time which is given to a year which is equal to 31536000 s. 
          orbital speed = (9.424 x 10¹¹ m)/31536000 s

               orbital speed = 29883.307 m/s

Hence, the orbital speed of the Earth is ~29883.307 m/s.

(b) The mass of the sun is ~1.9891 x 10³⁰ kg. 
8 0
4 years ago
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