Question

ng this process? During an adiabatic process, an ideal gas does 25 J of work. What is the change in the internal (thermal) energy of the gas during this process? 25 J 0.00 J 50 J -50 J -25 J

Answer 1

Answer:

Δ U = - 25 J

Explanation:

Given that process is adiabatic ,that is why heat transfer is zero, Q= 0 .

Work done by gas ,W = 25 J

We know that ,from first law of thermodynamics

Q= Δ U + W

Q=Heat transfer

W=Work transfer

ΔU=Change in the internal energy

Now by putting the values in the above equation

0 = 25 + Δ U

Δ U = - 25 J

Therefore the change in the internal energy of the gas is -25 J.