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drek231 [11]
3 years ago
7

How many hydrogen atoms are in 5.70 mol of ammonium sulfide?

Chemistry
1 answer:
QveST [7]3 years ago
3 0
<span>There are 2.74603 * 10^25 hydrogen atoms. Ammonium sulfide is represented by (NH4)2S. This means that there are 8 hydrogen atoms total. There are also 8 mol of H in ammonium sulfide. We also need to use avogadro’s number of 6.022 * 10^23. Hydrogen Atoms = 5.7mol * (8mol / 1mol) * 6.022 * 10^23 per mol Hydrogen atoms = 2.74603 * 10^25 hydrogen atoms.</span>
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She would observe a yellowish  solid precipitate which is the lead iodide and a white solid precipitate which is the potassium nitrate.

This is because the lead nitrate solution which contains particles of lead will mix with the potassium iodide solution containing  particles of iodide. Upon mixing,the  lead particles  from the Lead nitrate solution combines with the  iodide particles from Potassium iodide and form two compounds, a yellowish solid precipitate called lead iodide and a white solid  precipitate called Potassium nitrate.

The formation of entirely two new compounds is known as the double displacement reaction and can be written in a chemical equation as  

2KI(aq.)+Pb(NO₃)₂(aq.)------>2KNO₃(aq.)+PbI ₂(s)

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