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Vera_Pavlovna [14]
3 years ago
6

State of matter is the least In general, for any material, the compressible. ​

Chemistry
1 answer:
mihalych1998 [28]3 years ago
6 0

Answer:

Bulk matter can exist in three states: gas, liquid, and solid. Gases have the lowest density of the three, are highly compressible, and fill their containers completely

Explanation:

Please mark as brainliest

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How many significant figures are there in the measurement 64,000 mg?
Vsevolod [243]

I'm pretty sure that significant figures is just the amount of numbers there is. So, in this case I think the answer would be D. 5

4 0
3 years ago
I’ll really appreciate it if you help me out on this one .
Westkost [7]
1.
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5 0
3 years ago
2Pb(s) + O2(aq) + 4H+(aq) → 2H2O(l) + 2Pb2+(aq)
defon

Answer:

The answer to your question is 0.269 g of Pb

Explanation:

Data

Lead solution = 0.000013 M

Volume = 100 L

mass = 0.269 g

atomic mass Pb = 207.2 g

Chemical reaction

                        2Pb(s) + O₂(aq) + 4H⁺(aq) → 2H₂O(l) + 2Pb₂⁺(aq)

Process

1.- Calculate the mass of Pb in solution

Formula

Molarity = \frac{number of moles}{volume}

Solve for number of moles

Number of moles = Volume x Molarity

Substitution

Number of moles = 100 x 0.000013

Number of moles = 0.0013

2.- Calculate the mass of Pb formed.

                       207.2 g of Pb ----------------- 1 mol

                             x g             ----------------- 0.0013 moles

                        x = (0.0013 x 207.2) / 1

                        x = 0.269 g of Pb                                                                

8 0
3 years ago
Read 2 more answers
The element whose atomic number is 13 has how many valence electrons electron configuration
RideAnS [48]
It is in Group 3A = 3 valence electrons

Electron Config. = 1s2 2s2 2p6 3s2 3p1
4 0
3 years ago
A 2.741 g sample of a new organic material is combusted in a bomb calorimeter. the temperature of the calorimeter and its conten
lakkis [162]
(the heat bomb calorimeter gained)=(the heat material A gave)
r.h.s=25.57 kJ/⁰C * (26.80-24.33)= 63.16 kJ
2.741g of material A made 63.16kJ
the heat of combustion per gram = 63.16/2.741 kJ/g =24.04kJ/g
7 0
3 years ago
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