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Vera_Pavlovna [14]
3 years ago
6

State of matter is the least In general, for any material, the compressible. ​

Chemistry
1 answer:
mihalych1998 [28]3 years ago
6 0

Answer:

Bulk matter can exist in three states: gas, liquid, and solid. Gases have the lowest density of the three, are highly compressible, and fill their containers completely

Explanation:

Please mark as brainliest

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In a climatological sense, dryness is a function of both annual rainfall and ________.
Margarita [4]

Answer:

In a climatological sense, dryness is a function of both annual rainfall and evaporation

8 0
2 years ago
What is the speed of light of an orange light with a wavelength of 600nm and a frequency of 5.00x1014?
vovangra [49]

Answer:

3 × 10^8 m/s

Explanation:

The wavelength, can be calculated by using the following formula;

λ = v/f

Where;

λ = wavelength (m)

v = velocity/speed of light (m/s)

f = frequency (Hz)

According to the provided information in this question, λ = 600nm i.e. 600 × 10^-9m, f = 5.00 x 10^14 Hz

Hence, using λ = v/f

v = λ × f

v = 600 × 10^-9 × 5.00 x 10^14

v = 6 × 10^-7 × 5.00 x 10^14

v = 30 × 10^(-7 + 14)

v = 30 × 10^ (7)

v = 3 × 10^8 m/s

3 0
2 years ago
Currently this lab is run qualitatively asking only for whether a solution is acidic, neutral, or basic. If quantitative informa
crimeas [40]

Answer:

The only PH range which is not covered by any of the given components of the universal indicator is 7.6-8.0

Hence the PH range 7.6-8 can't be described using universal indicator.

8 0
3 years ago
Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r
denis23 [38]

Answer :

(1) The frequency of photon is, 3\times 10^{10}Hz

(2) The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = 1.0cm=0.01m     (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of photon

\lambda = wavelength of photon

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

\nu=\frac{3\times 10^8m/s}{0.01m}

\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz    (1Hz=1s^{-1})

The frequency of photon is, 3\times 10^{10}Hz

(2) Now we have to calculate the energy of photon.

Formula used :

E=h\times \nu

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})

E=1.988\times 10^{-23}J/photon

The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) Now we have to calculate the energy in J/mol.

E=1.988\times 10^{-23}J/photon

E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)

E=11.97J/mol

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

3 0
3 years ago
Read 2 more answers
What layer of earths atmosphere is the layer next to the earth
Pavlova-9 [17]

Answer:

troposphere

Explanation:

5 0
3 years ago
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