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3 years ago

Dehydration is a reversible process. Which of the two set-ups, distillation or

Chemistry

1 answer:

Nata [24]3 years ago

7 0

Answer:

Distillation will generate the most cyclohexene.

Explanation:

Let us assume following attached reaction for the synthesis of cyclohexene from cyclohexanol which attains equilibrium after certain time.

As shown in figure the cyclohexanol upon treatment with phosphoric acid undergoes dehydration reaction (removal of water) and produces cyclohexene. On the other hand cyclohexene reacts with water (hydration reaction) and produces cyclohexanol.

Now, if this reaction is allowed in a single flask it will attain equilibrium and will not generate the cyclohexene in high quantity. On the other hand if we apply Le Chatelier's principle ( removal of product moves the equilibrium in right direction) and distillate cyclohexene (boiling the cyclohexene to convert it into vapors and then collect it after condensation) will move the reaction in forward direction and will allow us to generate cyclohexene in high amounts.

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How many protons are in an element with an atomic number of 8 and a mass number of 18?

Natalija [7]

The answer is 8. atomic number: the number of protons in the nucleus of an atom.

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3 years ago

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Compute the boiling point of this solution:

ryzh [129]

Answer:

The boiling point of the solution is 101,42ºC

Explanation:

Formula for boiling point elevation is:

ΔT = Kb · molality . i

Water boils at 100ºC, at 1 atm.

NiSO4 ----> Ni2+ + SO4-2 (assume 100% ionization, the value of i, is 2)

Tº boiling point solution - Tº boiling point = Ebulloscopic constant . molality . Van't Hoff factor.

Tº bp solution - 100ºC = 0,512 ºC/molal . molality . 2

Molality means moles of solute in 1kg of solvent (1000g)

Molar mass NiSO4 = 154,75 g/m

Mass/ Molar mass = Moles --> 21,6 g / 154,75 g/m = 0,139 moles

These moles are in 100 g of H2O, so we have to make a rule of three to find, the moles in 1000g

100 g _________0,139 moles

1000 g _______ 1,39 moles (molality)

Tº bp solution - 100ºC = 0,512 ºC/molal . 1,39molal . 2

Tº bp solution = (0,512 ºC/molal . 1,39molal . 2) + 100ºC

Tº bp solution = 101,42ºC

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3 years ago

1. For a mixture of pure hexane and pure dimethylformamide, the dimethylformamide layer will be found as:______.a. the top layer

castortr0y [4]

Answer:

1. the bottom layer

2. aqueous HCI

3. the top layer

4.aqueous NaOH

5. mostly in the diethyl ether layer

Explanation:

Pure dimethylformamide is considerably more polar than hexane hence thee two solutions will form two phases with the pure dimethylformamide as the bottom layer.

If we want to extract aniline from chloroform, HCl must be added in order to give a salt that can be extracted into the aqueous layer.

For a mixture of methylene chloride and diethyl ether, the diethyl ether layer will be found as the top layer since it is considerably less polar than methylene chloride.

Benzyl alcohol can be extracted from a solution of chloroform by adding NaOH and extracting it into an aqueous layer.

A large partition coefficient for the extraction of naphthalene into diethyl ether from water means that naphthalene will be found mostly in the diethyl ether layer.

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2 years ago

If one molecule of glucose (C6H12O6) reacts completely with three molecules of oxygen (O2), what is the TOTAL number of atoms th

USPshnik [31]

Answer;

30 atoms

Explanation;

When glucose, C6H12O6, reacts with oxygen it produces carbon dioxide and water. If a molecule of glucose reacts completely with three molecules of oxygen, then 30 atoms would be produced because there are 24 atoms in glucose and 6 atoms in oxygen molecules.

The equation for the reaction would be;

C6H12O6 + 6O2(g) → 6CO2(g) + 6 H2O(l)

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3 years ago

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Porque sirve el teorema de pitagora

denis23 [38]

El teorema de Pitágoras se generaliza a espacios de dimensiones superiores. Algunas de las generalizaciones están lejos de ser obvias. El teorema de Pitágoras sirve como base de la fórmula de distancia euclidiana.

Espero que esto ayude, que tengan un día bendecido y maravilloso, ¡así como uno seguro! :-)

-Cutiepatutie

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3 years ago