Answer:
The percent composition of fluorine is 65.67%
Explanation:
Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.
That is, the percentage composition is the percentage by mass of each of the elements present in a compound.
The calculation of the percentage composition of an element is made by:
In this case, the percent composition of fluorine is:
percent composition of fluorine= 65.67%
<u><em>The percent composition of fluorine is 65.67%</em></u>
The correct answer is Hydroelectric (D)
Answer:
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First, we determine the number of moles of gas present using the ideal gas equation.
PV = nRT
n = PV / RT
n = (1.4 * 226.4) / (0.082 *(27 + 273.15))
n = 12.88
Next, we use the given percentages to find the moles of helium present
Moles of helium = 0.655 * 12.88
Moles of helium = 8.44
Next, we use the formula:
Mass = moles * molar mass
Mass of helium = 8.44 * 4
Mass of helium = 33.76 grams
Number of moles = 2.25 mols
volume <span>of the solution = 3.00 L
</span>
Therefore :
molarity = moles / volume
m = 2.25 / 3.00
=> 0.75 M