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3 years ago

What is the difference between a cup of tea at 95°C, and a drop of tea at 95°C?

Chemistry

1 answer:

nika2105 [10]3 years ago

5 0

Answer:

See the explanation below

Explanation:

Both the cup of coffee and drop of coffee have the Same temperature of 95°C.

Although the difference is the cup of coffee has more heat contained in it than the drop of coffee. An explanation is when we heat a cup of coffee it will take more time to Attain in 95°C while the drop of coffee will take less time

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What is the relationship between molar mass in grams per mole (g/mol) and average atomic mass in amu of each element?

navik [9.2K]

Answer:

The molar mass and atomic mass are essentially the same for an element

Explanation:

The molar mass of a substance can be obtained by dividing the mass of the substance by the no of moles of the substance present.

The atomic mass of an element is the number of protons and neutrons present in the substance.

These two measurements usually give the same values because they both make reference to the 1/12th the mass of carbon-12 for their measurement.

Because they both have the same reference point, though they have different calculating procedures, the results obtained will be similar.

8 0

4 years ago

The Mystery Salt

ryzh [129]

Question 1 :

To determine whether the salt is KCl or KNO3, one should look for the difference between them in terms of their physicochemical properties, such as their solubility.

Since we have the solubilité of KCl and KNO3, we can use the property of solubility to determine if the mystery salt is KCl or KNO3.

Question 2:

We will try to reproduce the conditions to determine the solubility of the salt at 37°C.

We will put into the beaker 100ml of water (equivalent to 100g) and dissolve a defined quantity of the salt (the number should be between the solubility of the KCl (37g) and KNO3 (30g) so between 30g and 37g).

Let's dissolve for example 32g of the salt, then, heat with the hotplate until the temperature of the beaker content will be 35 ° C (use the thermometer to determine the exact temperature).

Why?

This manipulation aims to determine the solubility of our mystery salt to know if it is KNO3 or KCl. In our conditions, we will obtain two different possibilities depending on if the salt is KCl or KNO3, this justifies why we took a quantity between 30g and 37g of salt.

If it is KNO3 (solubility of 30g/ml) we will observe a precipitation in the beaker because we exceed its solubility.

If it is KCl (37g/100) we will not observe a precipitate since we did not attempt the solubility of KCl

Question 3:

Finally to determine the composition of salt: we know that the solubility of KCL is 37g / 100ml (that is to say if we dissolve a higher mass (38g for example), we will observe a precipitation of salt) and that the solubility of KNO3 is 30g / 100ml (that is to say if we dissolve an upper mass (32g for example), we will observe a precipitation of salt)

In our experiment, 32g of salts were dissolved. If it is KCl, we will not observe a precipitate since the minimum concentration to start having a precipitate is not yet reached (37g / 100ml).

If it is KNO3, a precipitate will be observed since the minimum concentration to start having a precipitate is not yet reached (30g / 100ml).

6 0

3 years ago

Help please

gogolik [260]

Answer:

16 km/2 sec=8km/sec

Explanation:

4 0

3 years ago

The charge of an atom is determined by the-

Andrei [34K]

Answer:

electrons? not sure if im right tho

3 0

3 years ago

PLEASE HELP ASAP WITH THIS

slavikrds [6]

Answer:

Molar mass of Al = 26.98 g/mol

mass of Al = 33.0 g

we have below equation to be used:

number of mol of Al,

n = mass of Al/molar mass of Al

=(33.0 g)/(26.98 g/mol)

Molar mass of Cl2 = 70.9 g/mol

mass of Cl2 = 38.0 g

we have below equation to be used:

number of mol of Cl2,

n = mass of Cl2/molar mass of Cl2

=(38.0 g)/(70.9 g/mol)

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Part B

we have the Balanced chemical equation as:

2 Al + 3 Cl2 ---> 2 AlCl3

2 mol of Al reacts with 3 mol of Cl2

for 1.2231 mol of Al, 1.8347 mol of Cl2 is required

But we have 0.536 mol of Cl2

so, Cl2 is limiting reagent

we will use Cl2 in further calculation

Molar mass of AlCl3 = 1*MM(Al) + 3*MM(Cl)

= 1*26.98 + 3*35.45

= 133.33 g/mol

From balanced chemical reaction, we see that

when 3 mol of Cl2 reacts, 2 mol of AlCl3 is formed

mol of AlCl3 formed = (2/3)* moles of Cl2

= (2/3)*0.536

5 0

3 years ago