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Morgarella [4.7K]
3 years ago
12

You walk towards Starbucks southward for 14 meters and then west for 9 meters. The trip takes you 3 minutes to walk there. What

is your average velocity in meters per SECOND?
Physics
1 answer:
zimovet [89]3 years ago
8 0

Although you walked (14+9)= 23 meters of distance, you ended up only 16.64 meters from where you started. That's your "displacement".

Velocity = (displacement / (time)

Velocity = (16.64m)/(180s)

Velocity = 0.0925 m/s roughly Southwest.

(That's about 3.6 INCHES per second. Apparently, you really NEED that mocha java and it's associated drug.)

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health factors that could harm you or your offspring

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A 4.00-kg model rocket is launched, expelling 64.0 g of burned fuel from its exhaust at a speed of 675 m/s. What is the velocity
olga_2 [115]

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The velocity of the rocket is 7.8 m/s

Explanation:

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Think of the last five things you read. Now think of a type of reading you havent done recenty
GarryVolchara [31]

Answer:

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4)I too had a love story

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Explanation:

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6 0
3 years ago
A solid sphere has a radius of 0.200 m and a mass of 150.0 kg. how much work is required to get the sphere rolling with an angul
Allisa [31]

Here in this case we can use work energy theorem

As per work energy theorem

Work done by all forces = Change in kinetic Energy of the object

Total kinetic energy of the solid sphere is ZERO initially as it is given at rest.

Final total kinetic energy is sum of rotational kinetic energy and translational kinetic energy

KE = \frac{1}{2}Iw^2 +\frac{1}{2} mv^2

also we know that

I = \frac{2}{5}mR^2

w= \frac{v}{R}

Now kinetic energy is given by

KE = \frac{1}{2}(\frac{2}{5}mR^2)w^2 +\frac{1}{2} m(Rw)^2

KE = \frac{1}{5}mR^2w^2 +\frac{1}{2} mR^2w^2

KE = \frac{7}{10}mR^2w^2

KE = \frac{7}{10}*150*(0.200)^2(50)^2

KE = 10500 J

Now by work energy theorem

Work done = 10500 - 0 = 10500 J

So in the above case work done on sphere is 10500 J

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