Since Fluorine has 2 electrons in the s orbitals and 5 in the p orbitals of shell number 2, there is a total of 7 valence electrons.
Answer:
Terminal speed, v = 6901.07 m/s
Explanation:
It is given that,
Mass of the horizontal bar, m = 30 g = 0.03 kg
Length of the bar, l = 13 cm = 0.13 m
Magnetic field, 
Resistance, R = 1.2 ohms
We need to find the terminal speed oat which the bar falls. When terminal speed is reached,
Force of gravity = magnetic force
..................(1)
i is the current flowing
l is the length of the rod
Due to the motion in rods, an emf is induced in the coil which is given by :
, v is the speed of the bar
Equation (1) becomes,
v = 6901.07 m/s
So, the terminal speed at which the bar falls is 6901.07 m/s. Hence, this is the required solution.
Answer:
Inter Quartile Range
Explanation:
Quartile is a positional statistical average, which divided the data into 4 equal halves.
Q1 (Lower Quartile) has 25% data below it, 75% above it. Q3 (Upper Quartile) has 75% data below it, 25% above it.
Interquartile range is the measure used to calculate how far the lower & upper quartiles are.
Answer:
They will not meet
h-hX=1.2*g*t²
hX=v0*t-(1/2*g*t²)
Explanation:
fall h=1/2*g*t²
elevation time if v0=20 m/s te=v0/g=20 m/s /9.81 m/s²=2.0387s
hmax=v0²/(2*g)=(400 m²/s²)/19.62 m/s²2=20.387 m
free fall
t=2.0387s yields hX=1/2*g*t²=20.387 m
h-hX=200m - 20.387 m=179,613 m.
so, the second body has not enough initianoal speed to reach a meeting point
<h2>Answer:</h2>
<u>The correct option is</u><u> (C) its greater tensile strength </u>
<h2>Explanation:</h2>
Elasticity is the property of any material to return to its original shape when it is de-shaped. for example a spring comes to its original shape when it is stretched and then released. so the property that brings the spring back to its original form is called elasticity. On the other hand tensile strength is the maximum stress that a material can withstands before it breaks. Since polymers are also elastic so the greater tensile strength means greater elasticity.
