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3 years ago

Need help ASAP Thankss + BRAINLIST only for correct answer

Physics

2 answers:

spayn [35]3 years ago

7 0

Answer:

False

true

Hope this helps!

grigory [225]3 years ago

7 0

False true (person on top is correct)

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How much power is required to lift a 60 kg bed to the top of a 3 meter flight of stairs in 10 seconds?

Zigmanuir [339]

Answer:

176.58Watts

Explanation:

Power= work done /time

Where mass(m)=60kg

Height (h) =3m

Time(s)=10s

Force of gravity = 9.81m/s^2

Power=mgh/t

Power= (60kg) * (9.81m/s^2) * (3m)/10s

Power= 176.58Watts

8 0

3 years ago

Ballistic data obtained on a firing range show that aerodynamic drag reduces the speed of a .44 magnum revolver bullet from 250

m_a_m_a [10]

Answer:

0.363999909622

Explanation:

F = Force

m = Mass = 15.6 g

C = Drag coefficient

ρ = Density of air = 1.21 kg/m³

A = Surface area = $\dfrac{\pi}{4}d^2$

v = Terminal velocity = $v=210\ m/s$

s = Displacement = 150 m

$a=\dfrac{v^2-u^2}{2s}$

Force is given by

F = ma

$F=\dfrac{1}{2}\rho CAv^2\\\Rightarrow ma=\dfrac{1}{2}\rho CAv^2\\\Rightarrow m\dfrac{v^2-u^2}{2s}=\dfrac{1}{2}\rho CAv^2\\\Rightarrow C=2\times m\dfrac{v^2-u^2}{2s}\times\dfrac{1}{\rho Av^2}\\\Rightarrow C=2\times15.6\times 10^{-3}\dfrac{210^2-250^2}{2\times 150}\times\dfrac{1}{1.21\times\dfrac{\pi}{4}\times (11.2\times 10^{-3})^2(210)^2}\\\Rightarrow C=-0.363999909622$

The drag coefficient is 0.363999909622 (ignoring negative sign)

4 0

3 years ago

Consider a block of mass m attached to two springs, one on the left with spring constant k1 and one on the right with spring con

Andrew [12]

Answer:

$T= 2\pi\times sqrt(m/(k1+k2))$

Explanation:

When the block is displaced by x units

F= spring force

two springs are connected parallel

$F =-k_1x - k_2x$

Writing Newtons second law, F = ma

$-k_1x - k_2x =ma$

$-k_1x - k_2x = mx''$

a= x" ( differentiating x w.r.t time twice)

$x''+(k_1/m + k_2/m) x=0$

this the standard form of equation of oscillation spring mass system

This is the differential equation, x'' means that double differentiation of x , i.e, x'' is acceleration

since, Period $T=2\pi\sqrt{\frac{m}{K_{eq.}} }$

therefore,

$T= 2\pi\times sqrt(m/(k1+k2))$

3 0

3 years ago

Help me pls its for my science class i need to show my work

Lostsunrise [7]

Answer:

P = 5880 J

Explanation:

Given that,

The mass of the block, m = 30 kg

The block is sitting at a height of 20 m.

The block will have gravitational potential energy. The formula for gravitational potential energy is given by :

$P=mgh\\\\=30\times 9.8\times 20\\\\=5880\ J$

So, the required potential energy is equal to 5880 J.

6 0

3 years ago

What would happen to the coil if the current passing through it was too large?

Alborosie

When a current flows through coil, magnetic field is produced around the coil which induces emf also known as back emf. When current in the coil is increased, more magnetic field is produced which in turn increases the induced emf.

5 0

3 years ago