To develop this problem it is necessary to apply the concepts related to the Frequency according to the Period. Frequency is the number of repetitions per unit of time of any periodic event. The period is the length of time of each repetitive event, so the period is the reciprocal of the frequency.
The frequency of the metronome in seconds would then be
Since the frequency is inversely proportional to the period then
The correct answer is B. 375ms
Kinetic energy =(1/2) (mass) (speed²)
First object: KE = (1/2) (2 kg) (2m/s)² = 4 joules during the lift.
Second object: KE = (1/2) (4kg) (3 m/s)² = 18 joules during the lift.
The second object has more kinetic energy while it's being lifted
than the first object has while it's being lifted. Once they reach their
final heights and stop, neither object has any kinetic energy.
Hello
I think some details of the question are missing. However, I believe you are referring to a bob following some circular path. Therefore, the answer is "no": in fact, the centripetal force is equal on the earth and on the moon.
Keep in mind that the centripetal force is given by
where m is the mass, v the tangential velocity and r the radius of the circular motion. The mass m of the bob is the same on the earth and on the moon, so the centripetal force is the same.
Answer:
73.13°
Explanation:
According to snell's law,
n1sinθi = n2sinθr
n1/n2 = sinθr/sinθi
Critical angle is the angle of incidence at the denser medium when the angle of incidence at the less dense medium is 90°
This means i=C and r = 90°
The Snell's law formula will become
n1/n2 = sinC/sin90°
n2/n1 = 1/sinC
Where n1 is the refractive index of the less dense medium = 1.473
n2 is the refractive index of the denser medium = 1.540
Substituting the values in the formula,
1.540/1.473 = 1/sinC
1.045 = 1/sinC
SinC = 1/1.045
SinC = 0.957
C = sin^-1(0.957)
C = 73.13°
