1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andrew11 [14]
3 years ago
8

Which scenario involves kinetic energy transforming into potential energy? A. a book lying on a shelf B. a train traveling at a

constant speed C. a person drawing back the string of a bow and arrow D. a ball beginning to descend after being thrown upward
Physics
1 answer:
NeX [460]3 years ago
6 0
The answer is C.

The Kinetic energy which was exerted and experience pulling the string of a bow is kept as a potential energy at the end of the arrow in contact with the string. Once release from aim at stationary position the potential energy is again transformed.
You might be interested in
What is elasticity in polymer generally related to?
Andrej [43]
The elasticity of a polymer is primarily due to the structure of the molecule and the cross-linking between strands. Hydrogen bonding is a contributor to the shape of the molecule, but not a major player in terms of elasticity. We would have to answer "false".
<span>
</span>
6 0
3 years ago
Read 2 more answers
A 10-kg dog is running with a speed of 5.0 m/s. what is the minimum work required to stop the dog in 2.40 s?
ankoles [38]
Given required solution

M=10kg W=? W=Fd
v=5.0m/s F=mg
t=2.40s =10*10=100N
S=VT
=5m/s*2.4s
=12m
so W=12*100
W=1200J
4 0
3 years ago
Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m
Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}

Substituting,

V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

V_{cm} = 1.034m/s

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where here v_f is the velocity after the collision.

v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}

v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

v_f = 1.034m/s

8 0
3 years ago
what do scientific models predict will happen to Earths oceans if current trends continue unmitigated?
Margaret [11]

Answer:

I think that the answer is "Coral bleaching will continue to harm aquatic organisms.

Explanation:

Global warming causes the ocean temperatures to rise and also its pH to decrease due to increased dissolved carbon dioxide in the waters.

Due to the unfavorable temperatures and pH, the algae dissociate from the symbiotic relationship with coral polyps (as a survival mechanism) hence leaving the coral white (coral bleaching).

The symbiotic relationship is key for the survival of the coral polyps hence most die following the dissociation.

This upsets the reef ecosystem and affects all aquatic organisms that depend on the reef.

5 0
3 years ago
Read 2 more answers
A slingshot can project a pebble at a speed as high as 38.0 m/s. (a) If air resistance can be ignored, how high (in m) would a p
kipiarov [429]

Answer:

73.67 m

Explanation:

If projected straight up, we can work in 1 dimension, and we can use the following kinematic equations:

y(t) = y_0 + V_0 * t + \frac{1}{2} a t^2

V(t) = V_0 + a * t,

Where y_0 its our initial height, V_0  our initial speed, a the acceleration and t the time that has passed.

For our problem, the initial height its 0 meters, our initial speed its 38.0 m/s, the acceleration its the gravitational one ( g = 9.8 m/s^2), and the time its uknown.

We can plug this values in our equations, to obtain:

y(t) =  38 \frac{m}{s} * t - \frac{1}{2} g t^2

V(t) = 38 \frac{m}{s} - g * t

note that the acceleration point downwards, hence the minus sign.

Now, in the highest point, velocity must be zero, so, we can grab our second equation, and write:

0 m = 38 \frac{m}{s} - g * t

and obtain:

t = 38 \frac{m}{s} / g

t = 38 \frac{m}{s} / 9.8 \frac{m}{s^2}

t = 3.9 s

Plugin this time on our first equation we find:

y = 38 \frac{m}{s} * 3.9 s - \frac{1}{2} 9.8 \frac{m}{s^2} (3.9 s)^2

y=73.67 m

6 0
3 years ago
Other questions:
  • If the forces acting on an object produce a net force of zero, the forces are called
    10·1 answer
  • 6. A 7-kg bowling ball moving at 6.0 m/s strikes a 1-kg bowling pin. 11 we van
    6·1 answer
  • The speed an object needs to move away from the gravitational pull of the earth is called
    10·1 answer
  • Help me with this Weather Station Model by answering 5 questions. It is due tomorrow.
    7·1 answer
  • Why does a force perpendicular to an objects velocity change the direction of the velocity but not its magnitude
    5·1 answer
  • A 6,000 kg train car is moving to the right at 10 m/s and connects to a 4,000-kg train car that wasn't moving. What is the veloc
    10·1 answer
  • A piece of glass with a flat surface is at the bottom of a tank of water. If a ray of light traveling in the glass is incident o
    10·1 answer
  • When light passes from air into water at an angle of 60° from the normal, what is the angle of refraction? (40.6°)
    13·1 answer
  • Please help!!!!!!!!
    15·1 answer
  • HEY PLEASE HELP AM DESPERATE!!!!!!
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!