The surface area of a cube is:
S = 6l², making l the subject:
l = √(S/6)
While the volume is:
V = l³
If we substitute l to get:
V = (√(S/6))³
√(S/6) = ³√V
S/6 = (³√V)²
S = 6(³√V)² ⇒ 6V^(2/3)
Explanation:
I remember that notation! The expression

is the 1st law of thermodynamics and it refers to the heat supplied to the system dQ which is also a change in its internal energy dU. The first term is the <u>partial</u> derivative of the internal energy U with respect to temperature T while the volume V is kept constant, as denoted by the subscript V. The 2nd term is similar but this time, temperature is kept constant while its volume partial derivative is being taken.
Ah, memories!
Answer:
When argon changes from a gas to a liquid, the forces between the molecules become stronger so the particles become closer together and come into come into contact more often. The particles move at a less faster rate as the have less kinetic energy due to decrease in temperature. When argon changes from a liquid to a solid, the forces become even stronger so the particles are arranged in fixed positions and vibrate around a fixed point as they cannot move past each other
Answer: The correct answer is B
Explanation: The string is pulling right and the string is unraveling causing it to accelerate left