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max2010maxim [7]
3 years ago
10

A 10-kg dog is running with a speed of 5.0 m/s. what is the minimum work required to stop the dog in 2.40 s?

Physics
1 answer:
ankoles [38]3 years ago
4 0
Given required solution

M=10kg W=? W=Fd
v=5.0m/s F=mg
t=2.40s =10*10=100N
S=VT
=5m/s*2.4s
=12m
so W=12*100
W=1200J
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At the same time we know that the acceleration is given as the change of speed in a fraction of the time, that is

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Therefore the angular speed of a point on the outer edge of the tires is 66.67rad/s

At the same time the angular acceleration would be

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