12 cubic feet!! this may be it
Answer: 0.03855
Step-by-step explanation:
Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.
Its maximum safe load is 10000 pounds.
Let X denotes the weight of 50 people.
As per given ,
Population mean weight of 50 people =
Standard deviation of 50 people 
Then , the probability its maximum safe load will be exceeded =
![P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855](https://tex.z-dn.net/?f=P%28X%3E10000%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B10000-9500%7D%7B282.84%7D%29%5C%5C%5C%5C%3DP%28z%3E1.7671-8%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1.7678%29%5C%20%5C%20%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3DP%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3D1-0.96145%5C%20%5C%20%5C%20%5B%5Ctext%7B%20By%20p-value%20of%20table%7D%5D%5C%5C%5C%5C%3D0.03855)
Thus , the probability its maximum safe load will be exceeded = 0.03855
Answer:
The correct answer is 11 x squared + 2 y + x squared minus 3 y
Step-by-step explanation:
Just took the test on Edg. Hope it helps :)
Answer:
Part a) Daniel's age is 2 years
Part b) Kevin's age is 8 years
Step-by-step explanation:
<u><em>The question is </em></u>
Part a) How old is Daniel?
Part b) How old is Kevin?
Let
x ----> Kevin's age
y ----> Daniel's age
we know that
-----> equation A
----> equation B
Equate equation A and equation B

solve for y



therefore
Daniel's age is 2 years
<em>Find the value of x</em>
substitute the value of y in any of the two equations


therefore
Kevin's age is 8 years
Answer:
N = {13, 15, 17, 19}
Step-by-step explanation:
The natural numbers greater than 11 and less than 21 are:
12, 13, 14, 15, 16, 17, 18, 19 and 20
Odd numbers are numbers that have remainders when divided by 2. Out of the numbers above, the numbers with remainders when divided by 2 are 13, 15, 17 and 19.
Since N is the set of odd natural numbers greater than 11 and less than 21,
N = {13, 15, 17, 19}