The center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as:
x^2 + y^2 + 2gx + 2fy + c = 0
where:
(-g, -f) is the centre of the circle
Given the equations
x^2 +y^2 – 12x – 2y +12 = 0
Compare
2gx = -12x
g = -6
Simiarly
-2y = 2fy
f = -1
Centre = (6, 1)
Hence the center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
Learn more on equation of a circle here: brainly.com/question/1506955
Answer:
<em>m<ZXY - m<WXZ = m<WXY
</em>
Step-by-step explanation:
given:
point Z is in the interior of <WXY creating XZ.
<em>if m<WXZ = 20
</em>
<em> m<WXY = 100
</em>
find:
what would equation would you set up to find the missing angle measure?
solution:
<em>Since Z is interior of <WXY
</em>
<em>
m<ZXY - m<WXZ = m<WXY
</em>
<em><WXY = 100 - 20 = 80°
</em>
therefore, the equation would be <em>m<ZXY - m<WXZ = m<WXY </em>
Answer:
?= 63.15789474%
Step-by-step explanation:
Use cross multiply
Set ?=x
Answer:
4
Step-by-step explanation: i guessed and got it right
sorry if youre looking for an actual education!!
Answer:
2 3/4
Step-by-step explanation:
