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romanna [79]
2 years ago
7

How is an alkoxide ion formed??

Chemistry
2 answers:
umka2103 [35]2 years ago
7 0
The answer above is completely correct :)
ahrayia [7]2 years ago
5 0
An alkoxide is an organic functional group formed when a hydrogen atom is removed from a hydroxyl group of alcohol when reacted with a metal. It is the conjugate base of alcoho.
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Butoxors [25]

30 m/hrs (add me on discord if u have it Sipstic++#1460 )

8 0
3 years ago
Read 2 more answers
III. For the following four sections: If you are given the formula, name the
serious [3.7K]

Answer:

15.Potassium oxide

16.Calcium chloride

17.Aluminium sulphide

18.CaS

Explanation:

15.K is the chemical symbol of Potassium and generally the name of the non-metal at the end of a formula has the suffix '-ide' and since O is oxygen, the name becomes Potassium oxide.

16. The same applies here. Ca is Calcium and Cl is Chlorine but since its the non-metal at the end, it ends in -ide. So Calcium chloride.

17.The same applies here too. Al is Aluminium and S is Sulphur so Aluminium sulphide.

18. Calcium's symbol is Ca and that of Sulphur is S and that gives the formula CaS.

5 0
3 years ago
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brilliants [131]

Answer:

I'm thinking cooper but not sure

6 0
2 years ago
Given the balanced equation representing a reaction: 2na(s) + cl2(g) → 2nacl(s) + energy if 46 grams of na and 71 grams of cl2 r
igor_vitrenko [27]
Answer is: 2) 117g.
2Na + Cl₂ → 2NaCl
Step 1: calculate amount of substance of sodium and chlorine.
n(Na) = m(Na)÷M(Na) = 46g ÷ 23 g/mol = 2 mol.
n(Cl₂) = m(Cl₂)÷M(Cl₂) = 71g ÷ 71 g/mol = 1 mol.
Step 2: calculate amount of substance and mass of sodium-chloride.
Because both sodium and chlorine react completely, we can use both n to compare with n of NaCl.
n(Na) : n(NaCl) = 2:2, 2 mol : n(NaCl) = 2:2
n(NaCl) = 2mol, m(NaCl) = 2mol ·5805 g/mol = 117 g.

6 0
3 years ago
Select the correct answer.
Svetlanka [38]

Answer:

alcohol

I hope this helps you

7 0
3 years ago
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