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leva [86]
3 years ago
14

To test the resiliency of its bumper during low-speed collisions, a 2 840-kg automobile is driven into a brick wall. The car's b

umper behaves like a spring with a force constant 6.00 106 N/m and compresses 3.98 cm as the car is brought to rest. What was the speed of the car before impact, assuming no mechanical energy is transformed or transferred away during impact with the wall
Physics
1 answer:
Westkost [7]3 years ago
4 0

Answer:

V= 1.82 m/s

Explanation:

Given that

mass , m = 2840 kg

Spring constant ,K = 6 x 10⁶ N/m

Compression in the spring , x = 3.98 cm

Lets take speed of the car before impact = V

Now by using energy conservation

\dfrac{1}{2}Kx^2=\dfrac{1}{2}mV^2

Kx^2=mv^2

V=\sqrt{\dfrac{Kx^2}{m}}

Now by putting the values in the above equation

V=\sqrt{\dfrac{6\times 10^6\times (3.98\times 10^{-2})^2}{2840}}

V= 1.82 m/s

Therefore the speed of the car before impact will be 1.82 m/s.

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This question involves the concepts of the law of conservation of momentum and velocity.

The velocity of the eight ball is "5.7 m/s".

According to the law of conservation of momentum:

m_1u_1+m_2u_2=m_1v_1+m_2v_2

where,

m₁ = mass of number three ball = 5 g

m₂ = mass of the eight ball = 6 g

u₁ = velocity of the number three ball = 3 m/s

u₂ = velocity of the eight ball = - 1 m/s (negative sign due to opposite direction)

v₁ = final velocity of the three number ball = - 5 m/s

v₂ = final velocity of the eight ball = ?

Therefore,

(5 g)(3 m/s) + (6 g)(- 1 m/s) = (5 g)(- 5 m/s) + (6 g)(v₂)

v_2=\frac{34\ g.m/s}{6\ g}\\\\

<u>v₂ = 5.7 m/s</u>

<u></u>

Learn more about the law of conservation of momentum here:

brainly.com/question/1113396?referrer=searchResults

4 0
3 years ago
If a baseball is in space and someone hits it with a bat what does the ball do
Darina [25.2K]

Answer:

It's will fly like float

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Since in space there is no gravity that everything can float

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How many nanoseconds does it take light to travel 3.50 ft in vacuum?
Fiesta28 [93]
Answer:3.56 nanosecond

In this case, you are asked the time and given the light distance(3.5ft)
To answer this question you would need to know the velocity of light. Speed of light is <span>299792458m/s. Then the calculation would be:

time= distance/speed
time= 3.5 ft / (</span>299792458m/s) x 0.3048 meter/ 1 ft=  3.56 10^{-9} second or 3.56 nanosecond
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Pls help ASAP. This is astronomy but there isn't an option :)
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From largest to smallest they are: Universe, galaxy, solar system, star, planet, moon and asteroid.

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