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ololo11 [35]
3 years ago
9

A red cross helicopter takes off from headquarters and flies 120 km at 70 degrees south of west. There it drops off some relief

supplies, then flies 75 km at 60 degrees west of north to pick up three medics. If the helicoper then heads directly back to headquarters, find the distance and direction it should fly. Give your answers rounded to one decimal place.
Physics
1 answer:
fiasKO [112]3 years ago
3 0

Answer:

130 km at 35.38 degrees north of east

Explanation:

Suppose the HQ is at the origin (x = 0, y = 0)

So the coordinates of the helicopter after the 1st flight is

x_1 = -120cos70^o = -41.04 km

y_1 = -120sin70^o = -112.763 km

After the 2nd flight its coordinate would be:

x_2 = x_1 - 75sin60^o = -41.04 - 64.95 = -106km

y_2 = y_1 + 75cos60^o = -112.763 + 37.5 = -75.263 km

So in order to fly back to its HQ it must fly a distance and direction of

s = \sqrt{y_2^2 + x_2^2} = \sqrt{75.263^2 + 106^2} = \sqrt{5664.519169 + 11236} = \sqrt{16900.519169} = 130 km

tan\theta = \frac{y_2}{x_2} = \frac{75.263}{106} = 0.71

\theta = tan^{-1}0.71 = 0.62 rad \approx 35.38^o north of east

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1)

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F_y=2.70 N is the y-component

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F=\sqrt{(-7.14)^2+(2.70)^2}=7.63 N

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