All categories

2 years ago

Convert 700kg into grams

Physics

2 answers:

Hitman42 [59]2 years ago

8 0

Answer:

700 kilograms is equal to 700,000 grams

Explanation:

One kilogram has 1000 grams, or if you want the other way around, one gram is 1/1000th of one kilogram. If you follow this logic, we want to use the 'one kilogram has 1000 grams' "rule", so we would do some math here.

700 kg x 1000 g = ______ g

700*1000 = 700,000

700 kg = 700,000 g

Please let me know if I misunderstood and I hope this helped!

Verdich [7]2 years ago

5 0

Answer:

700,000g

Explanation:

1kg = 1000 Grams (or any kg x 1000)

You might be interested in

A dog jumps 0.80 m to catch a treat. The dog's displacement vector is shown below.

Brrunno [24]

Answer:D

Explanation:

It was right o khan academy

6 0

2 years ago

1. Bone has a Young’s modulus of about

Blababa [14]

As we know that

$Y = \frac{stress}{strain}$

now plug in all data into this

$1.8\times 10^{10} = \frac{1.68 \times 10^8}{strain}$

$strain = 9.33 \times 10^{-3}$

now from the formula of strain

$strain = \frac{\Delta L}{L}$

$9.33 \times 10^{-3} = \frac{\Delta L}{0.54}$

$\Delta L = 5.04 \times 10^{-3} m$

$\Delta L = 5.04 mm$

As we know that

pressure * area = Force

here we know that

$Area = 3.53 \times 11.6 = 40.95 m^2$

$P = 0.2 atm = 0.2 \times 1.01 \times 10^5 = 2.02\times 10^4 Pa$

now force is given as

$F = 40.95 \times (2.02\times 10^4) = 8.27 \times 10^5 N$

As we know that density of water will vary with the height as given below

$\rho = \frac{\rho_0}{1 - \frac{\Delta P}{B}}$

here we know that

$\Delta P = 2600 atm = 2600 \times 1.01 \times 10^5 = 2.63\times 10^8 Pa$

$B = 2.3 \times 10^9 N/m^2$

now density is given as

$\rho = \frac{1050}{1 - \frac{2.63\times 10^8}{2.3 \times 10^9}}$

$\rho = 1185.3 kg/m^3$

as we know that pressure changes with depth as per following equation

$P = P_o + \rho g h$

here we know that

$P = 3 P_0$

now we will have

$3P_0 = P_0 + \rho g h$

$2P_0 = \rho g h$

$2(1.01 \times 10^5) = 1025 (9.81)(h)$

here we will have

$h = 20.1 m$

so it is 20.1 m below the surface

Here net buoyancy force due to water and oil will balance the weight of the block

so here we will have

$mg = \rho_1V_1g + \rho_2V_2g$

$A(0.0476)979 = 922(A)(0.0476 - x) + 1000(A)(x)$

$46.6 = 43.89 - 922x + 1000x$

$x = 3.48 cm$

so it is 3.48 cm below the interface

5 0

3 years ago

a ball of mass 0.5 kg moving at 10 m/s collides with another ball of equal mass at rest. if the two balls move off together afte

nexus9112 [7]

Answer:

5 m/s

Explanation:

Here we can see there is no external force acted on a two masses when we consider the motion. If there is no external forces then momentum is conserved.

Initial momentum = Final momentum

0.5 × 10 = 1 × V

V = 5 m/s

7 0

3 years ago

A 40W lamp wastes 34 J of energy every second by heating its surroundings.

Artemon [7]

Answer:

$15\%$ .

Explanation:

The efficiency of a machine is the percentage of energy input that was turned into useful energy.

The power rating of this lamp is $40\; \rm W$ (same as $40\; \rm J \cdot s^{-1}$ ,) meaning that $40\; \rm J$ of energy is supplied to this lamp every second.

The question states that $34\; \rm J$ out of that $40\; \rm J$ of energy input would be turned into heat, which is not useful energy output in this scenario. Assuming that all other forms of energy loss is negligible. The rest of the $(40\; \rm J - 34\; \rm J) = 6\; \rm J$ of energy supplied to this lamp would be turned into useful energy output.

Thus, every second, this lamp would receive $40\; \rm J$ of energy input and would outputs $6\; \rm J$ of useful work. The efficiency of this lamp would be:

$\begin{aligned}& \text{Efficiency} \\ =\; & \frac{\text{Useful energy out}}{\text{Total energy in}} \times 100\% \\ =\; & \frac{6\; \rm J}{40\; \rm J} \times 100\%\\ =\; &15\% \end{aligned}$ .

4 0

2 years ago

What is the average speed of a car that traveled 300.0 miles in 5.5 hours?

Pavlova-9 [17]

<span>i think the average speed was 54.54 (mph)</span>

7 0

2 years ago

Read 2 more answers

Convert 700kg into grams​

Convert 700kg into grams