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Kitty [74]
4 years ago
7

How many miles of calcium oxide will be produced when 1.6 miles of iron (III) oxide react with calcium phosphate

Chemistry
1 answer:
Hitman42 [59]4 years ago
5 0
What is this for. Is it history
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PLEASE HELP!!!!
shtirl [24]
1) d

2) b because the independent variable is the thing you change/control in an experiment

3) c because the dependent variable is the thing being measured in an experiment

4)hmm it might be d, as c and a are both correct as different sized feeders would make it an unfair test and different types of food would as well

5) c

6) a

7) b obviously because if he activated them at different times then the ones activated last would have an advantage

6 0
4 years ago
Examples of two substances being mixed and the ​
yKpoI14uk [10]

Answer:

ocean water liquid and steel solid

6 0
4 years ago
PLEASE HELP ME THIS IS DUE RN I HAVE NO IDEA I WILL MARK BRAINLIEST I JUST NEED HELP
djverab [1.8K]

Answer:

3.45 × 10^5

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6 0
3 years ago
A buffer solution is made that is 0.347 M in H2C2O4 and 0.347 M KHC2O4.
irga5000 [103]

Answer:

1. pH = 1.23.

2. H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Explanation:

Hello!

1. In this case, for the ionization of H2C2O4, we can write:

H_2C_2O_4\rightleftharpoons HC_2O_4^-+H^+

It means, that if it is forming a buffer solution with its conjugate base in the form of KHC2O4, we can compute the pH based on the Henderson-Hasselbach equation:

pH=pKa+log(\frac{[base]}{[acid]} )

Whereas the pKa is:

pKa=-log(Ka)=-log(5.90x10^{-2})=1.23

The concentration of the base is 0.347 M and the concentration of the acid is 0.347 M as well, as seen on the statement; thus, the pH is:

pH=1.23+log(\frac{0.347M}{0.347M} )\\\\pH=1.23+0\\\\pH=1.23

2. Now, since the addition of KOH directly consumes 0.070 moles of acid, we can compute the remaining moles as follows:

n_{acid}=0.347mol/L*1.00L=0.347mol\\\\n_{acid}^{remaining}=0.347mol-0.070mol=0.277mol

It means that the acid remains in excess yet more base is yielded due to the effect of the OH ions provided by the KOH; therefore, the undergone chemical reaction is:

H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Which is also shown in net ionic notation.

Best regards!

4 0
3 years ago
Su şeker karışımını ayırma yöntemi nedir arkadaşlar
Alinara [238K]
<span>Suda karıştırıldıysa, kaynatma ile hacmi azaltmayı deneyebilirsiniz, ancak bir veya daha fazla çözüm bulunmaması durumunda çok uzun sürecektir. Çözeltiye fazla aseton ilavesi, filtrelenebilen tuzu çöktürmelidir. Asetondan buharlaşma şeker üretecektir.</span>
3 0
3 years ago
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