Answer:
i think it's eutrophication
Answer:
ΔHrxn = -635.14kJ/mol
Explanation:
We can make algebraic operations of reactions until obtain the desire reaction and, ΔH of the reaction must be operated in the same way to obtain the ΔH of the desire reaction (Hess's law). Using the reactions:
(1)Ca(s) + 2 H+(aq) → Ca2+(aq) + H2(g) ΔH = 1925.9 kJ/mol
(2) 2H2(g) + O2 g) → 2 H2O(l) ΔH = −571.68 kJ/mole
(3) CaO(s) + 2 H+(aq) → Ca2+(aq) + H2O(l) ΔH = 2275.2 kJ/mole
Reaction (1) - (3) produce:
Ca(s) + H2O(l) → H2(g) + CaO(s)
ΔH = 1925.9kJ/mol - 2275.2kJ/mol = -349.3kJ/mol
Now this reaction + 1/2(2):
Ca(s) + ½ O2(g) → CaO(s)
ΔH = -349.3kJ/mol + 1/2 (-571.68kJ/mol)
<h3>ΔHrxn = -635.14kJ/mol</h3>
Answer:
Explanation:
Since 1 mole of Fe reacted and 1 mole of Cu is produced.
Mass = molar mass × number of moles
Molar mass of Fe = 56 g/mol
Molar mass of Cu = 63.5 g/mol
Mass of Fe = 56 × 1
= 56 g
Mass of Cu = 63.5 × 1
= 63.5 g
Therefore, the statement is not correct.
You have a. 3, b. 2, e. 6, f. 3, i. 1
