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muminat
3 years ago
12

A student found the mass of the irregular solid to be 6.4 grams and the volume on the graduated cylinder rose from 6.8 mL to 7.7

mL. What is the identity of the substance? Question 4 options: Zinc Alcohol Aluminum Copper
Chemistry
1 answer:
Sedaia [141]3 years ago
7 0

Density, Volume and Mass

3. A metal weighing 7.101 g is placed in a graduated cylinder containing 33.0 mL of water. The water

level rose to the 37.4 mL mark.

a) Calculate the density of the metal (in g/mL).

b) If you were to do this with an equal mass of aluminum (d = 2.7 g/mL), how high would the water rise?

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Which of these is not a response to internal stimul?
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3 years ago
a stock solution has a concentration of 0.30 m clo2 and is diluted to become a 0.20 m solution with a volume of 0.050 l. what wa
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The stock solution has a volume of 0.208L. When diluted, a stock solution with a concentration of 0.30 m clo2 becomes a 0.20 m stock solution with a volume of 0.050.

A three-dimensional space's occupied volume is measured. It is frequently measured numerically with SI-derived units (such the cubic metre and litre) or with other imperial units (such as the gallon, quart, cubic inch). Volume and length are related in how they are defined (cubed).

A highly concentrated stock solution, often prepared as a 10x concentrated solution, can be described as a stock solution since it can be diluted to create a working solution. In order to prepare complex solutions with numerous constituents, stock solutions can also be utilized as a component.

0.3M*v = 0.125M*0.50L

V=0.208L

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1 year ago
I break and shatter easily and I am not shiny. What am I?
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7 0
2 years ago
If 00810 mol neon gas at the particular temperature and pressure occupies a volume of 214 mL ehat volume would 0.00684 mol neon
Grace [21]

Answer:

V_2=181mL

Explanation:

Hello,

In this case, Avogadro's relationship allows us to relate the moles and the volume of a gas at an initial condition and an a final one as shown below:

\frac{n_1}{V_1}=\frac{n_2}{V_2}

Thus, the volume that 0.00684 mol of neon the same pressure and temperature is computed below as required:

V_2=\frac{V_1*n_2}{n_1}=\frac{214mL*0.00684mol}{0.00810mol}  \\\\V_2=181mL

Best regards.

6 0
3 years ago
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