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ladessa [460]
3 years ago
11

A motorboat traveling with a current can go 160 km in 4 hours. against the current it takes 5 hours to go the same distance. Fin

d the speed of motorboat and speed of current.
Physics
1 answer:
MatroZZZ [7]3 years ago
3 0
<h2>Speed of motorboat is 36 km/hr and speed of current is 4 km/hr.</h2>

Explanation:

Let speed of motor boat be m and speed of current be c.

A motorboat traveling with a current can go 160 km in 4 hours.

   Distance = 160 km

   Time = 4 hours

    Speed = m + c

   We have

            Distance = Speed x Time

            160 = (m+c) x 4

            m + c = 40     --------------------- eqn 1

Against the current it takes 5 hours to go the same distance.

   Distance = 160 km

   Time = 5 hours

    Speed = m - c

   We have

            Distance = Speed x Time

            160 = (m-c) x 5

            m - c = 32     --------------------- eqn 2

eqn 1 + eqn 2

           2m = 40 + 32

             m = 36 km/hr

Substituting in eqn 1

               36 + c = 40

                      c = 4 km/hr

Speed of motorboat is 36 km/hr and speed of current is 4 km/hr.

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Which surface winds blow between the subtropical high and the equator
sasho [114]

Answer:

trade winds

Explanation:

In tropics regions on the lower portion of earth's atmosphere the surface winds are observed in prevailing pattern. In northern hemisphere the trade wind predominantly blows from north east. In southern hemisphere it flows from south east. Subtropical high and the equator is in between these areas.

Thus, trade wind blow between the subtropical high and the equator.


7 0
3 years ago
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Whats a good air time and maximum height
serg [7]

Answer: Time to reach max. height is the time taken by it to reach the topmost position whereas time of flight is the overall time taken by it, i.e. till it reach down back to the thrower or launcher. And also time of flight is double the time to reach maximum height.

Explanation:

5 0
3 years ago
A Juggler is juggling a uniform rod one end of which is coated in tar and burning. He is holding the rod by the opposite end and
lyudmila [28]

The vertical speed of the rod varies inversely as the rotational speed for a given number of complete rotations

The equation that gives the vertical velocity, v₀ is  \, \underline{v_0=  \dfrac{ g \cdot \pi \cdot n}{  \omega_0   }}

Reason:

<em>From a similar question, the given parameters appear to be correctly given as follows;</em>

<em>The vertical speed of the rod = v₀</em>

<em>Angular velocity of the = ω₀</em>

Required;

The value of, v₀, so that the rod has made exactly, <em>n</em>, number of turns when it returns to his hand

Where;

n = An integer

Solution;

The time the rod spends in the air is given as follows;

Height, \ h = u \cdot t - \dfrac{1}{2} \cdot g \cdot t^2

Where;

g = Acceleration due to gravity

t = Time of motion

When the rod returns to his hand, we have, h = 0, therefore;

0 = u \cdot t - \dfrac{1}{2} \cdot g \cdot t^2

u \cdot t = \dfrac{1}{2} \cdot g \cdot t^2

t^2 =  \dfrac{u \cdot t }{\dfrac{1}{2} \cdot g } =   \dfrac{2 \cdot u \cdot t }{g }

Time, \ t =    \dfrac{2 \cdot u  }{g }

We have;

Angular \ velocity, \ \omega_0 = \dfrac{ 2 \cdot \pi \cdot n}{t} \ (required)

\omega_0 = \dfrac{ 2 \cdot \pi \cdot n}{  \dfrac{2 \cdot v_0  }{g }} =  \dfrac{ g \cdot \pi \cdot n}{  v_0 }

Therefore;

The \ vertical \ velocity, \, \underline{v_0=  \dfrac{ g \cdot \pi \cdot n}{  \omega_0   }}

Learn more here:

brainly.com/question/14140053

4 0
3 years ago
Short essay Question
Reptile [31]
<h2>Hello! :)</h2>

Answer:

In wind turbines, the blades rotate due to the wind.

Explanation:

In wind turbines, the blades rotate due to the wind.<u> While the blade rotates the generator connected to it also rotates.</u> Thus the <u>kinetic energy from the wind initiates the electric generator which in turn produces the electricity.</u>

Thus the<u> kinetic energy of the wind is converted to electricity.</u>

<u></u>

Hope this helps!

Have a Wonderful Friday!

-Good Luck on your Homework- :)

6 0
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I got 21 once I answer that question
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