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3 years ago

11

A motorboat traveling with a current can go 160 km in 4 hours. against the current it takes 5 hours to go the same distance. Fin

d the speed of motorboat and speed of current.

1 answer:

MatroZZZ [7]3 years ago

3 0

<h2>Speed of motorboat is 36 km/hr and speed of current is 4 km/hr.</h2>

Explanation:

Let speed of motor boat be m and speed of current be c.

A motorboat traveling with a current can go 160 km in 4 hours.

Distance = 160 km

Time = 4 hours

Speed = m + c

We have

Distance = Speed x Time

160 = (m+c) x 4

m + c = 40 --------------------- eqn 1

Against the current it takes 5 hours to go the same distance.

Distance = 160 km

Time = 5 hours

Speed = m - c

We have

Distance = Speed x Time

160 = (m-c) x 5

m - c = 32 --------------------- eqn 2

eqn 1 + eqn 2

2m = 40 + 32

m = 36 km/hr

Substituting in eqn 1

36 + c = 40

c = 4 km/hr

Speed of motorboat is 36 km/hr and speed of current is 4 km/hr.

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andreev551 [17]

Answer:

3.24×10⁸ J, or 324 MJ

Explanation:

"kWh" is a kilowatt-hour. It's the energy used by 1 kilowatt of power after one hour.

A kilowatt is a kilojoule per second.

90 kWh

= 90 kW × 1 hr

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The microwaves in a certain microwave oven have a wavelength of 12.2 cm. How wide must this oven be so that it will contain five

leva [86]

Answer:

a

$l = 0.305 \ m$

b

$f = 3.0*10^{11} \ Hz$

Explanation:

From the question we are told that

The wavelength is $\lambda = 12.2 \ cm = 0.122 \ m$

The number of antinodal planes of the electric field considered is n = 5

The width is mathematically represented as

$l = \frac{ n \lambda}{2}$

$l = \frac{5 * 0.122 }{ 2}$

$l = 0.305 \ m$

Generally the frequency the errors was made is mathematically represented as

$f = \frac{c}{\lamda_k}$

Here c is the speed of light with value $c = 3.0*10^{8} \ m/s$

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$\lambda_k = \frac{ \lambda * \frac{0.04}{2} }{n/2}$

$\lambda_k = \frac{0.122*0.02}{5/2}$

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konstantin123 [22]

Answer:

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Explanation:

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Angle between magnetic field and area vector $\theta =$ 21°

Form the formula of torque in case of magnetic field,

г $= MB \sin \theta$

Where $M =$ magnetic moment

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г $= IAB \sin 21$

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г $=2.4 \times 10^{-2}$ Nm

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SIZIF [17.4K]

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Learn more:

Ocean current brainly.com/question/4117397

#learnwithBrainly

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