Question

Isaac throws an apple straight up from 1.0 m above the ground, reaching a maximum height of 35 meters. Neglecting air resistance, what is the ball's velocity when it hits the ground?

Answer 1

26.2005 m/s will be the velocity of the apple right when it hits the ground and the initial velocity would be 25.8235 m/s

so Vf=26.2005
and Vi=25.8235

the velocity difference is due to the apple having an initial height of 1 meter

Answer 2

The ball's velocity when it hits the ground is about 26 m/s

Further explanation

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

This problem is about kinematics.

At the maximum height , the velocity of the ball is 0 m/s

Given:

maximum height = h = 35 m

velocity at the maximum height = 0 m/s

gravitational accelerationg = 9.8 m/s²

Unknown:

velocity at the ground = v = ?

Solution:

$v^2 = u^2 + 2gh$

$v^2 = 0^2 + 2(9.8)(35)$

$v^2 = 686$

$v = \sqrt {686}$

$v = 7\sqrt{14} ~ m/s$

$v \approx 26 ~ m/s$

Conclusion:

The ball's velocity when it hits the ground is about 26 m/s

Learn more

• Velocity of Runner : brainly.com/question/3813437
• Kinetic Energy : brainly.com/question/692781
• Acceleration : brainly.com/question/2283922
• The Speed of Car : brainly.com/question/568302

Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate