All categories

3 years ago

A 100 Ohm, 200 Ohm, and 400 Ohm resistors are in parallel with each other. What is the equivalent

Physics

2 answers:

krok68 [10]3 years ago

7 0

Answer:

1/R = 1/R1 + 1/R2 + 1/R3

1/1 + 1/2 + 1/4 = 1 + .5 + .25 = 1.75

1/1.75 = .572

multiplying this by 100 gives us

R = 57.2 ohms

The smallest resistor (100 ohms) will draw the most current

(One can also use R = R1 R2 R3 / (R1 R2 + R1 R3 + R2 R3)

ryzh [129]3 years ago

6 0

Hi there!

We can use the following equation to solve for equivalent resistance:

$\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}$

We can plug in the givens and solve.

$\frac{1}{R_T} = \frac{1}{100} + \frac{1}{200} + \frac{1}{400} \\\\\frac{1}{R_T} = 0.175\\\\R_T = \frac{1}{0.175} = \boxed{57.143 \Omega}$

The resistor that would draw the most current is the 100 Ohm resistor because current chooses the path of LEAST RESISTANCE. This can also be proved mathematically with the following:

For resistors in parallel, the POTENTIAL DIFFERENCE (VOLTAGE) is the same.

Since I = V/R, a smaller 'R' means a larger 'I'. Thus, the smallest resistor would have the greatest current through it.

You might be interested in

(II) How much work did the movers do (horizontally) pushing a 46.0-kg crate 10.3 m across a rough floor without acceleration, if

Gwar [14]

Answer:

2324 J

Explanation:

The formula for work is:

$W=F*d$

where $F$ is the force applied, and $d$ is the distance moved, in this case $d=10.3m$

and we need to find $F.$

Since the crate is not moving up or down, we conclude that the <u>normal force must be equal to the weight </u>of the object:

$N=w$

where $N$ is the normal force and $w$ is the weight, which is: $w=mg$ , where g is the gravitational acceleration $g=9,81m/s^2$ and $m$ is the mass $m=46kg$ .

---------

Thus the normal force is:

$N=mg$

Now, the force due to the friction is defined as:

$f=\mu N=\mu mg$

where $\mu$ is the coefficient of friction, $\mu =0.5$

So, for the crate to move, the force applied must be equal to the frictional force:

$F=f\\F=\mu mg$

And now that we know the force we can calculate the work:

$W=F*d\\W=\mu mg*d$

substituting known values:

$W=(0.5)(46kg)(9.81m/s^2)(10.3)\\W=2324J$

5 0

3 years ago

Read 2 more answers

Which of the following is a benefit of physical activity?

zaharov [31]

Answer:

Explanation:

better concentration

5 0

3 years ago

Read 2 more answers

A playground slide is inclined 40°. If a boy with a mass of 32 kg slides down for -3meters. How much work is done by gravity on

telo118 [61]

Answer:

the work done by gravity on the boy is 604.62 J

Explanation:

Given;

distance the boy slides, d = 3 m

angle of inclination of the playground, θ = 40⁰

mass of the boy, m = 32 kg

The vertical height, h, above the ground through which the boy falls represents the height of the triangle which is the opposite side.

The distance through which the boy slides, d, represents the hypotenuse side of the right triangle.

$sin \theta = \frac{opposite }{hypotenuse} \\\\sin \theta = \frac{h}{d} \\\\h = dsin\theta\\\\h = 3 \times sin(40^0)\\\\h = 1.928 \ m$

The work done by gravity on the boy is calculated as;

W = P.E = mgh

= 32kg x 9.8m/s² x 1.928m

= 604.62 J

Therefore, the work done by gravity on the boy is 604.62 J

8 0

3 years ago

What are two ways of changing PE?

Anna35 [415]

Potential energy is simply energy that can be but isn't yet
it can also be changed by putting it into motion or setting it off by using force or enacting gravity by dropping it.

6 0

3 years ago

The strength of the electric field 0.5 m from a 6 µc charge is n/c. (use k = 8.99 × 109 n•meters squared per coulomb squared and

diamong [38]

53....................................

Explanation:

6 0

2 years ago