The overall efficiency of the conversion is 6.93%.
<h3>What is the overall efficiency?</h3>
We know that generation of electricity from radioactive fuels is one of the major ways by which we can generate electricity in many countries. Now the efficiency of each of the steps have been shown in the question;
- Conversion efficiency = 35%
- Transmission efficiency = 90%
- Light efficiency = 22%
Overall efficiency = (0.35 * 0.90 * 0.22) * 100 = 6.93%
The energy is obtained from;
6.7X10^13 J * 6.93/100
= 4.6 * 10^12 J
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Missing parts;
The atomic number of uranium-235 is 92, its half-life is 704 million years and the radioactive decay of l kg of 235U releases 6.7X10^13 J. Generally, radioactive material is considered safe after 10 half-lives.
Assume that a nuclear powerplant can convert energy from 235U into electricity with an efficiency of 35%, the electrical transmission lines operate at 90% efficiency, and flourescent lights operate at 22% efficiency.
1.) What is the overall efficiency of converting the energy of 235U into flourescent light?
2.) How much energy from 1 kg of 235U is converted into flourescent light?
Answer:
Kinetic Enerrgy = 12744000 J or 12.744 MJ
Explanation:
Given Data:
Mass of fragment = m =1770 kg ;
Estimated speed = v = 120 m/sec ;
Solution:
As we know that
Kinetic energy = K.E = (1/2)mv²
By putting the values, we get
K.E = 0.5*1770*120²
K.E = 12744000 J
or
K.E = 12.744 MJ
So, the kinetic energy of lead-lined vault when it landed was 12.744MJ approximately.
When the image distance is positive, the image is on the same side of the mirror as the object, and it is real and inverted. When the image distance is negative, the image is behind the mirror, so the image is virtual and upright. A negative m means that the image is inverted. Positive means an upright image.
The correct answer is 1.2 m/s
: mv+mv=mv+mv
(0.5kg)(2m/s)+(0.4kg)(0m/s)=(0.5kg)v+(0.4kg)(1m/s)
= 1kg*m/s=(0.5kg)v+0.4kg*m/s
=1kg*m/s-0.4kg*m/s=(0.5kg)v
=0.6kg*m/s=(0.5kg)v
to solve for v we divide both side by 0.5kg
v=1.2m/s
3,89,988 cm/min is the linear velocity
Given,
Diameter of CD = 12 cm
So, Radius of CD = 6 cm
CD is spinning at 10350 rev/min
Firstly , convert rev/min into rad/min
1 rev = 2π radians
10350 rev/min = 10350 × 2π
= 64998 rad/min
Formula used,
where,
is the Linear velocity
is the radius
is the angular velocity
= 6 cm × 64998rad/min
= 3,89,988 cm/min
Thus, linear velocity for any edge point of a 12-cm-diameter CD (compact disc) spinning at 10,350 rev/min is 389988 cm/min.
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