<h2> The potential and kinetic energy of airplane are affected by these factors </h2>
Explanation:
When airplane rises up , it requires potential energy . This potential energy can be taken from the kinetic energy of airplane .
Thus if the speed of wind is larger , it can either oppose the motion of velocity or can favour the velocity of airplane . By which its kinetic energy is effected .
If the weight of airplane is changed , it will effect the potential energy required . Thus heavier plane requires higher potential energy for attaining the same height .
Thus these two factor has important role in the flight of airplane .
In an Internal Combustion Engine, the fuel is singed in the chamber or vessel. Example: Diesel or Petrol motor utilized as a part of Cars.
The internal engine has its vitality touched off in the barrel, as 99.9% of motors today. In an External Combustion Engine, the inner working fuel is not consumed. Here the liquid is being warmed from an outer source. The fuel is warmed and extended through the interior instrument of the motor bringing about work. Eg. Steam Turbine, Steam motor Trains. An outer burning case is a steam motor where the warming procedure is done in a kettle outside the motor.
Answer:
a. mechanical; require a medium to travel through
Explanation:
Longitudinal, transverse and surface waves are types of mechanical waves. For example, within the longitudinal waves are the sound waves, which needs a medium to propagate like the air. This is why sound does not travel in a vacuum.
And an example of a transverse wave is the waves that form in the water when a rock is thrown (ripples), these waves need a medium (the water) to propagate.
On the other hand, electromagnetic waves such as light waves do not need a medium to propagate, this is why we can see the light of distant stars because their light travels through the vacuum until it reaches us.
So, the answer is:
Transverse, surface, and longitudinal waves are all mechanical waves because they require a medium to travel through .
Answer:
0.0061 J
Explanation:
Parameters given:
Number of turns, N = 111
Radius of turn, r = 2.11 cm = 0.0211 m
Resistance, R = 14.1 ohms
Time taken, t = 0.125 s
Initial magnetic field, Bin = 0.669 T
Final magnetic field, Bfin = 0 T
The energy dissipated in the resistor is given as:
E = P * t
Where P = Power dissipated in the resistor
Power, P, is given as:
P = V² / R
Hence, energy will be:
E = (V² * t) / R
To find the induced voltage (EMF), V:
EMF = [-(Bfin - Bin) * N * A] / t
A is Area of coil
EMF = [-(0 - 0.669) * 111 * pi * 0.0211²] / 0.125
EMF = 0.83 V
Hence, the energy dissipated will be:
E = (0.83² * 0.125) / 14.1
E = 0.0061 J
