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gregori [183]
4 years ago
5

Amy throws a softball through the air. What are the different forces acting on the ball while it’s in the air?

Physics
2 answers:
Tema [17]4 years ago
5 0

Answer:

An applied force, drag force and gravitational force.

Explanation:

When Amy throws a softball through the air, there is some force that acts on it.  The forces that are experienced by the ball in the air as follows :

The softball experiences an applied force as a result of Amy’s throw. As the ball moves, it experiences a drag from the air it passes through. It also experiences a downward pull because of gravity.

The applied force is defined as the force applied by the person who is throwing the ball.

Drag is equivalent to the frictional force that is applied in the opposite direction.

The gravitational force always acts in downward direction.

aniked [119]4 years ago
4 0
An applied force<span> is a </span>force<span> that is </span>applied<span> to an object by a person or another object.
An attractive force is a force of an attraction (where object are attracted by each other). Gravitation is an example of attractive force.
</span>Normal force<span> is the component, perpendicular to the surface (surface being a plane) of contact.
</span><span>The softball experiences an applied force as a result of Amy’s throw. As the ball moves, it experiences attractive force from the air it passes through. It also experiences a downward pull because of the normal force.
Solution A.</span>
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A race car accelerates from rest to a velocity of +90 m/s over a distance of 423m. Determine the acceleration of the race car.
dlinn [17]

Answer:

9.57m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Final velocity  = 90m/s

Distance  = 423m

Unknown:

Acceleration of the race car  = ?

Solution:

To solve this problem, we should apply one of the appropriate motion equations;

      V²  = U²   + 2as

Where V is the final velocity

           U is the initial velocity

           a is the acceleration

           s is the distance

  90²  = 0²  + 2 x a x 423

  8100 = 846a

      a  = 9.57m/s²

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4 years ago
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2 years ago
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A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the wate
Simora [160]

Answer: Option A: 22.5 m

Explanation:

A stone is dropped from a tower. The initial velocity of the stone, u = 0.

Height of the tower, y = 100 m

Let the depth of the well be d.

Time taken of the drop of the stone, t = 5 s

The stone falls under acceleration due to gravity g = 9.81 m/s²

We will use second equation of motion:

s = u t + 0.5 g t²

⇒100 m + d = 0 + 0.5 × 9.81 m/s²× (5.00 s)²

⇒d = (122.6 - 100) m = 22.6 m ≅ 22.5 m

Thus, the correct option is A. The depth of the well is 22.5 m.

3 0
4 years ago
Which describes freefall
Sati [7]
A motion where gravity is the only force acting upon it
6 0
4 years ago
A force of 20 N acts on a smaller piston of a hydraulic press with an area of ​​10 dm2. How much force does the liquid act on a
Amiraneli [1.4K]

Answer:

166.6 N

Explanation:

Given that,

Force, F₁ = 20 N

Area, A₁ = 10 dm² = 1000 cm²

We need to find the new force if the area of the larger piston is 120 cm². According to Pascal's law,

F_1A_1=F_2A_2\\\\F_2=\dfrac{F_1A_1}{A_2}\\\\F_2=\dfrac{20\times 1000}{120}\\\\F_2=166.7\ N

So, the force on the larger piston is equal to 166.7 N.

8 0
3 years ago
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