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Rzqust [24]
3 years ago
11

The alkanes are a homologous series of compounds containing only carbon and hydrogen that have the general formula

ps://tex.z-dn.net/?f=C_nH_%7B2n%2B2%7D" id="TexFormula1" title="C_nH_{2n+2}" alt="C_nH_{2n+2}" align="absmiddle" class="latex-formula">. Members of this series include butane (C₄H₁₀), 3,3-dimethylpentane (C₇H₁₆), hexane (C₆H₁₄), and heptane (C₇H₁₆).
The boiling points for a set of compounds in a homologous series can be qualitatively predicted using intermolecular force strengths. Using their condensed structural formulas, rank the homologous series for a set of alkanes by their boiling point.
Chemistry
1 answer:
AnnZ [28]3 years ago
8 0

Answer:

Heptane > hexane> 3,3-dimethylpentane > butane

Explanation:

All things being equal, it is expected that the boiling point of the members of the alkane homologous series increase as we move down the group.

Hence for example, butane is expected to have a higher boiling point than ethane. Another important factor we would be considering in this answer is the presence of a branched alkane amongst the answers in the question. A straight-chain alkane will have a boiling point which is higher than that of a branched-chain alkane due to the greater surface area in contact, thus the greater van der Waals forces, between adjacent molecules

Now if we are to rank the compounds on the basis of boiling point, the answer is as follows:

Heptane > hexane > 3,3-dimethylpentane> butane

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Answer:

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The volume of the 0.15 M LiOH solution required to react with 50 mL of 0.4 M HCOOH to the equivalence point is 133.3 mL

<h3>Balanced equation </h3>

HCOOH + LiOH —> HCOOLi + H₂O

From the balanced equation above,

The mole ratio of the acid, HCOOH (nA) = 1

The mole ratio of the base, LiOH (nB) = 1

<h3>How to determine the volume of LiOH </h3>
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  • Molarity of base, LiOH (Mb) = 0.15 M
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MaVa / MbVb = nA / nB

(0.4 × 50) / (0.15 × Vb) = 1

20 / (0.15 × Vb) = 1

Cross multiply

0.15 × Vb = 20

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Vb = 133.3 mL

Thus, the volume of the LiOH solution needed is 133.3 mL

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