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Rzqust [24]
3 years ago
11

The alkanes are a homologous series of compounds containing only carbon and hydrogen that have the general formula

ps://tex.z-dn.net/?f=C_nH_%7B2n%2B2%7D" id="TexFormula1" title="C_nH_{2n+2}" alt="C_nH_{2n+2}" align="absmiddle" class="latex-formula">. Members of this series include butane (C₄H₁₀), 3,3-dimethylpentane (C₇H₁₆), hexane (C₆H₁₄), and heptane (C₇H₁₆).
The boiling points for a set of compounds in a homologous series can be qualitatively predicted using intermolecular force strengths. Using their condensed structural formulas, rank the homologous series for a set of alkanes by their boiling point.
Chemistry
1 answer:
AnnZ [28]3 years ago
8 0

Answer:

Heptane > hexane> 3,3-dimethylpentane > butane

Explanation:

All things being equal, it is expected that the boiling point of the members of the alkane homologous series increase as we move down the group.

Hence for example, butane is expected to have a higher boiling point than ethane. Another important factor we would be considering in this answer is the presence of a branched alkane amongst the answers in the question. A straight-chain alkane will have a boiling point which is higher than that of a branched-chain alkane due to the greater surface area in contact, thus the greater van der Waals forces, between adjacent molecules

Now if we are to rank the compounds on the basis of boiling point, the answer is as follows:

Heptane > hexane > 3,3-dimethylpentane> butane

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If 45.6 grams of water decompose at 301 Kelvin and 1.24 atmospheres, how many liters of oxygen gas can be produced? Show all of
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This reaction is called the electrolysis of water. The balanced reaction is:

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5 0
3 years ago
A 1.2 L weather balloon on the ground has a temperature of 25°C and is at atmospheric pressure (1.0 atm). When it rises to an el
musickatia [10]

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Explanation:

Hello,

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4 0
3 years ago
Read 2 more answers
URGENT CHEMISTRY EXPERT!
vovangra [49]

Answer:

Part 1: 7.42 mL; Part 2: 3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ 2Cu₃(PO₄)₂(s)

Explanation:

Part 1. Volume of reactant

(a) Balanced chemical equation.

\rm 2Na_{3}PO_{4} + 3CuCl_{2} \longrightarrow Cu_{3}(PO_{4})_{2} + 6NaCl

(b) Moles of CuCl₂

\text{Moles of CuCl}_{2} =\text{ 16.7 mL CuCl}_{2} \times \dfrac{\text{0.200 mmol CCl}_{2}}{\text{1 mL CuCl}_{2}} =  \text{3.340 mmol CuCl}_{2}

(c) Moles of Na₃PO₄

The molar ratio is 2 mmol Na₃PO₄:3 mmol CuCl₂

\text{Moles of Na$_{3}$PO}_{4} =  \text{3.340 mmol CuCl}_{2} \times \dfrac{\text{2 mmol Na$_{3}$PO}_{4}}{\text{3 mmol CuCl}_{2}} =\text{2.227 mmol Na$_{3}$PO}_{4}

(d) Volume of Na₃PO₄

V = \text{2.227 mmol Na$_{3}$PO}_{4}\times \dfrac{\text{1 mL Na$_{3}$PO}_{4}}{\text{0.300 mmol Na$_{3}$PO}_{4}} = \text{7.42 mL Na$_{3}$PO}_{4} \\\\\text{The reaction requires $\large \boxed{\textbf{7.42 mL Na$_{3}$PO}_{4}}$}

Part 2. Net ionic equation

(a) Molecular equation

\rm 2Na_{3}PO_{4}(\text{aq}) + 3CuCl_{2}(\text{aq}) \longrightarrow Cu_{3}(PO_{4})_{2}(\text{s}) + 6NaCl(\text{aq})

(b) Ionic equation

You write molecular formulas for the solids, and you write the soluble ionic substances as ions.

According to the solubility rules, metal phosphates are insoluble.

6Na⁺(aq) + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + 6Cl⁻(aq) ⟶ Cu₃(PO₄)₂(s) + 6Na⁺(aq) + 6Cl⁻(aq)  

(c) Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

<u>6Na⁺(aq)</u> + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + <u>6Cl⁻(aq)</u> ⟶ Cu₃(PO₄)₂(s) + <u>6Na⁺(aq)</u> + <u>6Cl⁻(aq)</u>  

The net ionic equation is

3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ Cu₃(PO₄)₂(s)

7 0
3 years ago
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